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Addition_Question_One.java
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139 lines (67 loc) · 1.86 KB
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package ThreadPractice;
/**
* Created by kush on 08/09/16.
*/
/**
* If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.
Find the sum of all the multiples of 3 or 5 below 1000.
*/
public class Addition_Question_One {
private int i;
private int count =0;
Object lock = new Object();
Object lock2 = new Object();
public void increment_i(String ThreadName){
synchronized (lock) {
if (i % 3 == 0 || i % 5 == 0 && i<1000) {
System.out.print(i + "\t" + ThreadName + "\t" + (count+=i) + "\n");
// count = count + i;
}
i++;
}
}
public static void main(String args[]) {
Addition_Question_One main = new Addition_Question_One();
main.dowork();
}
private void dowork() {
Thread t1 = new Thread(new Runnable() {
@Override
public void run() {
process("Thread 1");
}
});
Thread t2= new Thread(new Runnable() {
@Override
public void run() {
process("Thread 2");
}
});
Thread t3= new Thread(new Runnable() {
@Override
public void run() {
process("Thread 3");
}
});
Thread t4= new Thread(new Runnable() {
@Override
public void run() {
process("Thread 4");
}
});
Thread t5= new Thread(new Runnable() {
@Override
public void run() {
process("Thread 5");
}
});
t1.start();
t2.start();
t3.start();
}
private void process(String ThreadName) {
while (i < 1000) {
increment_i(ThreadName);
}
}
}