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Solution.java
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57 lines (46 loc) · 1.62 KB
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package src.leetcode;
import src.common.node.TreeNode;
import src.utils.GeneralUtils;
import src.utils.PrintTreeUtils;
import java.util.ArrayList;
import java.util.Deque;
import java.util.LinkedList;
import java.util.List;
class Solution {
public List<String> generateParenthesis(int n) {
List<String> list = new ArrayList<String>();
generate(0, 0, n,"",list);
return list;
}
private void generate(int left, int right, int total, String s,List<String> list){
if( left == total && right == total){
list.add(s);
return;
}
if( left < total) generate(left + 1, right, total, s + "(",list);
if( left > right) generate(left, right + 1, total, s + ")",list);
}
public boolean isValidBST(TreeNode root) {
Deque<TreeNode> stack = new LinkedList<TreeNode>();
double inorder = -Double.MAX_VALUE;
while (!stack.isEmpty() || root != null) {
while (root != null) {
stack.push(root);
root = root.left;
}
root = stack.pop();
// 如果中序遍历得到的节点的值小于等于前一个 inorder,说明不是二叉搜索树
if (root.val <= inorder) {
return false;
}
inorder = root.val;
root = root.right;
}
return true;
}
public static void main(String[] args) {
TreeNode treeNode = GeneralUtils.constructNormalBinaryTree(new Integer[]{5,4,6,null,null,3,7});
PrintTreeUtils.printTreeNode(treeNode);
new Solution().isValidBST(treeNode);
}
}