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132-pattern.java
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456. 132 Pattern
Given a sequence of n integers a1, a2, ..., an, a 132 pattern is a subsequence ai, aj, ak such that i < j < k and ai < ak < aj. Design an algorithm that takes a list of n numbers as input and checks whether there is a 132 pattern in the list.
Note: n will be less than 15,000.
Example 1:
Input: [1, 2, 3, 4]
Output: False
Explanation: There is no 132 pattern in the sequence.
Example 2:
Input: [3, 1, 4, 2]
Output: True
Explanation: There is a 132 pattern in the sequence: [1, 4, 2].
Example 3:
Input: [-1, 3, 2, 0]
Output: True
Explanation: There are three 132 patterns in the sequence: [-1, 3, 2], [-1, 3, 0] and [-1, 2, 0].
//https://discuss.leetcode.com/topic/67881/single-pass-c-o-n-space-and-time-solution-8-lines-with-detailed-explanation
public class Solution {
public boolean find132pattern(int[] nums) {
int s3 = Integer.MIN_VALUE;
Stack<Integer> st = new Stack<Integer>();
for(int i = nums.length-1; i >= 0; i--){
if(nums[i] < s3) {
return true;
}
while(!st.empty() && nums[i] > st.peek() ) {
s3 = st.pop();
}
st.push(nums[i]);
}
return false;
}
}