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46_TranslateNumbersToStrings.cpp
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/*******************************************************************
Copyright(c) 2016, Harry He
All rights reserved.
Distributed under the BSD license.
(See accompanying file LICENSE.txt at
https://github.com/zhedahht/CodingInterviewChinese2/blob/master/LICENSE.txt)
*******************************************************************/
//==================================================================
// 《剑指Offer——名企面试官精讲典型编程题》代码
// 作者：何海涛
//==================================================================
// 面试题46：把数字翻译成字符串
// 题目：给定一个数字，我们按照如下规则把它翻译为字符串：0翻译成"a"，1翻
// 译成"b"，……，11翻译成"l"，……，25翻译成"z"。一个数字可能有多个翻译。例
// 如12258有5种不同的翻译，它们分别是"bccfi"、"bwfi"、"bczi"、"mcfi"和
// "mzi"。请编程实现一个函数用来计算一个数字有多少种不同的翻译方法。
#include <string>
#include <iostream>
using namespace std;
#if 0
int GetTranslationCount(const string& number);
int GetTranslationCount(int number)
{
if(number < 0)
return 0;
string numberInString = to_string(number);
return GetTranslationCount(numberInString);
}
int GetTranslationCount(const string& number)
{
int length = number.length();
int* counts = new int[length];
int count = 0;
for(int i = 0; i < length; i++)
{
if(i == 0)
counts[i] = 1;
else if(i == 1)
{
if(number[0] == '1' || (number[0] == '2' && number[1] >= '0' && number[1] <= '5'))
counts[i] = 2;
else
counts[i] = 1;
}
else
{
if(number[i - 1] == '1' || (number[i - 1] == '2' && number[i] >= '0' && number[i] <= '5'))
counts[i] = counts[i - 2] + counts[i - 1];
else
counts[i] = counts[i - 1];
}
count = counts[i];
}
delete[] counts;
return count;
}
#endif
int GetTranslationCount(const string& number);
int GetTranslationCount(int number)
{
if(number < 0)
return 0;
string numberInString = to_string(number);
return GetTranslationCount(numberInString);
}
int GetTranslationCount(const string& number)
{
int length = number.length();
int* counts = new int[length];
int count = 0;
for(int i = length - 1; i >= 0; --i)
{
count = 0;
if(i < length - 1)
count = counts[i + 1];
else
count = 1;
if(i < length - 1)
{
int digit1 = number[i] - '0';
int digit2 = number[i + 1] - '0';
int converted = digit1 * 10 + digit2;
if(converted >= 10 && converted <= 25)
{
if(i < length - 2)
count += counts[i + 2];
else
count += 1;
}
}
counts[i] = count;
}
count = counts[0];
delete[] counts;
return count;
}
// ====================测试代码====================
void Test(const string& testName, int number, int expected)
{
if(GetTranslationCount(number) == expected)
cout << testName << " passed." << endl;
else
cout << testName << " FAILED." << endl;
}
void Test1()
{
int number = 0;
int expected = 1;
Test("Test1", number, expected);
}
void Test2()
{
int number = 10;
int expected = 2;
Test("Test2", number, expected);
}
void Test3()
{
int number = 125;
int expected = 3;
Test("Test3", number, expected);
}
void Test4()
{
int number = 126;
int expected = 2;
Test("Test4", number, expected);
}
void Test5()
{
int number = 426;
int expected = 1;
Test("Test5", number, expected);
}
void Test6()
{
int number = 100;
int expected = 2;
Test("Test6", number, expected);
}
void Test7()
{
int number = 101;
int expected = 2;
Test("Test7", number, expected);
}
void Test8()
{
int number = 12258;
int expected = 5;
Test("Test8", number, expected);
}
void Test9()
{
int number = -100;
int expected = 0;
Test("Test9", number, expected);
}
int main(int argc, char* argv[])
{
Test1();
Test2();
Test3();
Test4();
Test5();
Test6();
Test7();
Test8();
Test9();
return 0;
}