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test3.java
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84 lines (64 loc) · 2.67 KB
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public class test {
static int M=10000;
public static void main(String[] args) {
// TODO Auto-generated method stub
int[][] weight1 = {//邻接矩阵
{0,3,2000,7,M},
{3,0,4,2,M},
{M,4,0,5,4},
{7,2,5,0,6},
{M,M,4,6,0}
};
int[][] weight2 = {
{0,10,M,30,100},
{M,0,50,M,M},
{M,M,0,M,10},
{M,M,20,0,60},
{M,M,M,M,0}
};
int start=0;
int[] shortPath = Dijsktra(weight2,start);
for(int i = 0;i < shortPath.length;i++)
System.out.println("从"+start+"出发到"+i+"的最短距离为:"+shortPath[i]);
}
public static int[] Dijsktra(int[][] weight,int start){
int n = weight.length; //顶点个数
int[] shortPath = new int[n]; //存放从start到其他各点的最短路径
String[] path=new String[n]; //存放从start到其他各点的最短路径的字符串表示
for(int i=0;i<n;i++)
path[i]=new String(start+"-->"+i);
int[] visited = new int[n]; //标记当前该顶点的最短路径是否已经求出,1表示已求出
//初始化,第一个顶点求出
shortPath[start] = 0;
visited[start] = 1;
for(int count = 1;count <= n - 1;count++) //要加入n-1个顶点
{
int k = -1; //选出一个距离初始顶点start最近的未标记顶点
int dmin = Integer.MAX_VALUE;
for(int i = 0;i < n;i++)
{
if(visited[i] == 0 && weight[start][i] < dmin)
{
dmin = weight[start][i];
k = i;
}
}
System.out.println("k="+k);
//将新选出的顶点标记为已求出最短路径,且到start的最短路径就是dmin
shortPath[k] = dmin;
visited[k] = 1;
//以k为中间点,修正从start到未访问各点的距离
for(int i = 0;i < n;i++)
{ // System.out.println("k="+k);
if(visited[i] == 0 && weight[start][k] + weight[k][i] < weight[start][i]){
weight[start][i] = weight[start][k] + weight[k][i];
path[i]=path[k]+"-->"+i;
}
}
}
for(int i=0;i<n;i++)
System.out.println("从"+start+"出发到"+i+"的最短路径为:"+path[i]);
System.out.println("===========================");
return shortPath;
}
}