|
| 1 | +import java.util.Arrays; |
| 2 | + |
| 3 | +/** |
| 4 | + * Given an array S of n integers, find three integers in S such that the sum is closest to a given number, target. |
| 5 | + * Return the sum of the three integers. You may assume that each input would have exactly one solution. |
| 6 | + * For example, given array S = {-1 2 1 -4}, and target = 1. |
| 7 | + * The sum that is closest to the target is 2. (-1 + 2 + 1 = 2). |
| 8 | + * <p/> |
| 9 | + * The solution is to use two nested loops to enumerate the combination of num[i], num[j], |
| 10 | + * and then use binary search to locate the numbers which may have the closest distance with the target. |
| 11 | + * The complexity of this algorithm is O(n^2 logn). |
| 12 | + */ |
| 13 | +public class ThreeSumClosest { |
| 14 | + public static void main(String[] args) { |
| 15 | + int[] a = new int[]{-1, 2, 1, -4}; |
| 16 | + int target = 1; |
| 17 | + |
| 18 | + int[] result = threeSumClosest(a, target); |
| 19 | + System.out.println(Arrays.toString(result)); |
| 20 | + |
| 21 | + int[] result1 = threeSumClosest1(a, target); |
| 22 | + System.out.println(Arrays.toString(result1)); |
| 23 | + } |
| 24 | + |
| 25 | + public static int[] threeSumClosest(int[] a, int target) { |
| 26 | + int[] result = new int[3]; |
| 27 | + |
| 28 | + if (a.length < 3) |
| 29 | + return result; |
| 30 | + |
| 31 | + Arrays.sort(a); |
| 32 | + |
| 33 | + int min_distance = Integer.MAX_VALUE; |
| 34 | + |
| 35 | + for (int i = 0; i < a.length - 2; i++) { // extra two element needed, so i<a.length-2 |
| 36 | + for (int j = i + 1; j < a.length - 1; j++) { // extra one element needed, so j<a.length-1 |
| 37 | + int val = target - a[i] - a[j]; |
| 38 | + int begin = j + 1, end = a.length - 1, mid, sum; |
| 39 | + int[] temp = new int[3]; |
| 40 | + while (begin <= end) { |
| 41 | + mid = (begin + end) / 2; |
| 42 | + |
| 43 | + if (a[mid] == val) { |
| 44 | + result[0] = a[i]; |
| 45 | + result[1] = a[j]; |
| 46 | + result[2] = a[mid]; |
| 47 | + return result; |
| 48 | + } else if (a[mid] < val) { |
| 49 | + begin = mid + 1; |
| 50 | + } else { |
| 51 | + end = mid - 1; |
| 52 | + } |
| 53 | + } |
| 54 | + if (begin > a.length - 1) { |
| 55 | + sum = a[i] + a[j] + a[end]; |
| 56 | + temp[0] = a[i]; |
| 57 | + temp[1] = a[j]; |
| 58 | + temp[2] = a[end]; |
| 59 | + } else if (end < j + 1) { |
| 60 | + sum = a[i] + a[j] + a[begin]; |
| 61 | + temp[0] = a[i]; |
| 62 | + temp[1] = a[j]; |
| 63 | + temp[2] = a[begin]; |
| 64 | + } else { |
| 65 | + int d1 = a[i] + a[j] + a[begin]; |
| 66 | + int d2 = a[i] + a[j] + a[end]; |
| 67 | + |
| 68 | + int d1_distance = Math.abs(d1 - target); |
| 69 | + int d2_distance = Math.abs(d2 - target); |
| 70 | + if (d1_distance < d2_distance) { |
| 71 | + sum = d1; |
| 72 | + temp[0] = a[i]; |
| 73 | + temp[1] = a[j]; |
| 74 | + temp[2] = a[begin]; |
| 75 | + |
| 76 | + } else { |
| 77 | + sum = d2; |
| 78 | + temp[0] = a[i]; |
| 79 | + temp[1] = a[j]; |
| 80 | + temp[2] = a[end]; |
| 81 | + |
| 82 | + } |
| 83 | + |
| 84 | + } |
| 85 | + if (Math.abs(sum - target) < min_distance) { |
| 86 | + min_distance = Math.abs(sum - target); |
| 87 | + |
| 88 | + result = temp.clone(); |
| 89 | + } |
| 90 | + |
| 91 | + } |
| 92 | + } |
| 93 | + return result; |
| 94 | + } |
| 95 | + |
| 96 | + // non binary search |
| 97 | + public static int[] threeSumClosest1(int[] a, int target) { |
| 98 | + int[] result = new int[3]; |
| 99 | + |
| 100 | + if (a.length < 3) |
| 101 | + return result; |
| 102 | + |
| 103 | + Arrays.sort(a); |
| 104 | + |
| 105 | + int min_distance = Integer.MAX_VALUE; |
| 106 | + int x, y, z, sum, temp_distance; |
| 107 | + for (int i = 0; i < a.length - 2; i++) { |
| 108 | + x = a[i]; |
| 109 | + for (int j = i + 1, k = a.length-1; j < k; ) { |
| 110 | + y = a[j]; |
| 111 | + z = a[k]; |
| 112 | + sum = x+y+z; |
| 113 | + temp_distance = Math.abs(sum-target); |
| 114 | + if(sum < target){ |
| 115 | + |
| 116 | + if(temp_distance < min_distance){ |
| 117 | + min_distance = temp_distance; |
| 118 | + result[0] = x; |
| 119 | + result[1] = y; |
| 120 | + result[2] = z; |
| 121 | + } |
| 122 | + j++; |
| 123 | + } else if(sum > target){ |
| 124 | + if(temp_distance < min_distance){ |
| 125 | + min_distance = temp_distance; |
| 126 | + result[0] = x; |
| 127 | + result[1] = y; |
| 128 | + result[2] = z; |
| 129 | + } |
| 130 | + k--; |
| 131 | + }else { |
| 132 | + result[0] = x; |
| 133 | + result[1] = y; |
| 134 | + result[2] = z; |
| 135 | + return result; |
| 136 | + |
| 137 | + } |
| 138 | + |
| 139 | + } |
| 140 | + } |
| 141 | + |
| 142 | + return result; |
| 143 | + |
| 144 | + } |
| 145 | +} |
0 commit comments