对列表内的元素进行排序，奇数在前，偶数在后。如果你高兴的话也可以反过来呀。 使用列表解析式解决！
# -*- coding: utf-8 -*-
from random import randrange
def odd_even(seq):
odd = [i for i in lst if i % 2 != 0]
even = [i for i in lst if i % 2 == 0]
return odd + even
if __name__ == "__main__":
lst = [randrange(100) for _ in range(10)]
print(odd_even(lst))什么，你想要奇偶数排好序的。行呀，导入之前自己写的插入排序！走起
from random import randrange
from insert_sort import *
def odd_even(seq):
odd = [i for i in lst if i % 2 != 0]
odd = insert_sort(odd)
even = [i for i in lst if i % 2 == 0]
even = insert_sort(even)
return odd + even
if __name__ == "__main__":
lst = [randrange(100) for _ in range(10)]
print(odd_even(lst))