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| 1 | +问题分析:首先我们需要看清楚题目,多线程、顺序打印、然后就是几个线程交替顺序打印; |
| 2 | + |
| 3 | +首先看下输出结果: |
| 4 | + |
| 5 | +``` |
| 6 | +
|
| 7 | +thread-0:0 |
| 8 | +thread-1:1 |
| 9 | +thread-2:2 |
| 10 | +thread-0:3 |
| 11 | +thread-1:4 |
| 12 | +thread-2:5 |
| 13 | +thread-0:6 |
| 14 | +thread-1:7 |
| 15 | +thread-2:8 |
| 16 | +thread-0:9 |
| 17 | +thread-1:10 |
| 18 | +thread-2:11 |
| 19 | +thread-0:12 |
| 20 | +thread-1:13 |
| 21 | +thread-2:14 |
| 22 | +thread-0:15 |
| 23 | +thread-1:16 |
| 24 | +thread-2:17 |
| 25 | +thread-0:18 |
| 26 | +thread-1:19 |
| 27 | +thread-2:20 |
| 28 | +thread-0:21 |
| 29 | +thread-1:22 |
| 30 | +thread-2:23 |
| 31 | +thread-0:24 |
| 32 | +thread-1:25 |
| 33 | +thread-2:26 |
| 34 | +thread-0:27 |
| 35 | +thread-1:28 |
| 36 | +thread-2:29 |
| 37 | +thread-0:30 |
| 38 | +thread-1:31 |
| 39 | +thread-2:32 |
| 40 | +thread-0:33 |
| 41 | +thread-1:34 |
| 42 | +thread-2:35 |
| 43 | +thread-0:36 |
| 44 | +thread-1:37 |
| 45 | +thread-2:38 |
| 46 | +thread-0:39 |
| 47 | +thread-1:40 |
| 48 | +thread-2:41 |
| 49 | +thread-0:42 |
| 50 | +thread-1:43 |
| 51 | +thread-2:44 |
| 52 | +thread-0:45 |
| 53 | +thread-1:46 |
| 54 | +thread-2:47 |
| 55 | +thread-0:48 |
| 56 | +thread-1:49 |
| 57 | +thread-2:50 |
| 58 | +thread-0:51 |
| 59 | +thread-1:52 |
| 60 | +thread-2:53 |
| 61 | +thread-0:54 |
| 62 | +thread-1:55 |
| 63 | +thread-2:56 |
| 64 | +thread-0:57 |
| 65 | +thread-1:58 |
| 66 | +thread-2:59 |
| 67 | +thread-0:60 |
| 68 | +thread-1:61 |
| 69 | +thread-2:62 |
| 70 | +thread-0:63 |
| 71 | +thread-1:64 |
| 72 | +thread-2:65 |
| 73 | +thread-0:66 |
| 74 | +thread-1:67 |
| 75 | +thread-2:68 |
| 76 | +thread-0:69 |
| 77 | +thread-1:70 |
| 78 | +thread-2:71 |
| 79 | +thread-0:72 |
| 80 | +thread-1:73 |
| 81 | +thread-2:74 |
| 82 | +thread-0:75 |
| 83 | +thread-1:76 |
| 84 | +thread-2:77 |
| 85 | +thread-0:78 |
| 86 | +thread-1:79 |
| 87 | +thread-2:80 |
| 88 | +thread-0:81 |
| 89 | +thread-1:82 |
| 90 | +thread-2:83 |
| 91 | +thread-0:84 |
| 92 | +thread-1:85 |
| 93 | +thread-2:86 |
| 94 | +thread-0:87 |
| 95 | +thread-1:88 |
| 96 | +thread-2:89 |
| 97 | +thread-0:90 |
| 98 | +thread-1:91 |
| 99 | +thread-2:92 |
| 100 | +thread-0:93 |
| 101 | +thread-1:94 |
| 102 | +thread-2:95 |
| 103 | +thread-0:96 |
| 104 | +thread-1:97 |
| 105 | +thread-2:98 |
| 106 | +thread-0:99 |
| 107 | +thread-1:100 |
| 108 | +
|
| 109 | +``` |
| 110 | + |
| 111 | +其实这个题目的重点就是怎么实现多个线程交替顺序打印,想一想,这里我们需要用到的就是线程间的通信,然后怎么通信呢? |
| 112 | +我们可以通过 synchronized + wait + notifyAll,或者 ReentrantLock + Condition + await + signalAll; |
| 113 | + |
| 114 | +知道了线程间怎么通信,然后就是在每个线程内部怎么实现了,是不是多个线程共用一把锁,然后自然数0-100是公共资源,让3个线程去消费; |
| 115 | + |
| 116 | +我们可以每个线程加上一个标号:0,1,2,来表示具体是哪个线程; |
| 117 | +通过一个计数器对3进行求余,余数和具体的线程标号去比较,只有当余数和线程标号相等的时候才进行打印(不等加入等待队列),打印完计数器进行自增; |
| 118 | +然后唤醒等待队列里面线程去获取锁,获取锁成功则继续执行以上步骤,否则加入锁的同步队列中,等待上一个线程唤醒; |
| 119 | + |
| 120 | +`用 synchronized 锁实现如下:` |
| 121 | + |
| 122 | +```java |
| 123 | +class PrintThread1 implements Runnable { |
| 124 | + private static final Object LOCK = new Object(); |
| 125 | + |
| 126 | + private static int count = 0; // 计数,同时确定线程是否要加入等待队列,还是可以直接去资源队列里面去获取数据进行打印 |
| 127 | + private LinkedList<Integer> queue; |
| 128 | + private Integer threadNo; |
| 129 | + |
| 130 | + public PrintThread1(LinkedList<Integer> queue, Integer threadNo) { |
| 131 | + this.queue = queue; |
| 132 | + this.threadNo = threadNo; |
| 133 | + } |
| 134 | + |
| 135 | + @Override |
| 136 | + public void run() { |
| 137 | + while (true) { |
| 138 | + synchronized (LOCK) { |
| 139 | + while (count % 3 != this.threadNo) { |
| 140 | + if (count >= 101) { |
| 141 | + break; |
| 142 | + } |
| 143 | + try { |
| 144 | + LOCK.wait(); |
| 145 | + } catch (InterruptedException e) { |
| 146 | + e.printStackTrace(); |
| 147 | + } |
| 148 | + } |
| 149 | + |
| 150 | + if (count >= 101) { |
| 151 | + break; |
| 152 | + } |
| 153 | + |
| 154 | + Integer val = this.queue.poll(); |
| 155 | + System.out.println("thread-" + this.threadNo + ":" + val); |
| 156 | + count++; |
| 157 | + |
| 158 | + LOCK.notifyAll(); |
| 159 | + } |
| 160 | + } |
| 161 | + } |
| 162 | +} |
| 163 | +``` |
| 164 | + |
| 165 | +`用 ReentrantLock 锁实现如下:` |
| 166 | + |
| 167 | +```java |
| 168 | +class PrintThread2 implements Runnable { |
| 169 | + private static final ReentrantLock lock = new ReentrantLock(); |
| 170 | + private static final Condition c = lock.newCondition(); |
| 171 | + |
| 172 | + private static int count = 0; //作为计数,同时也作为资源;因为这道题目是自然数作为资源,所以正好可以公用; |
| 173 | + private Integer threadNo; |
| 174 | + |
| 175 | + public PrintThread2(Integer threadNo) { |
| 176 | + this.threadNo = threadNo; |
| 177 | + } |
| 178 | + |
| 179 | + @Override |
| 180 | + public void run() { |
| 181 | + while (true) { |
| 182 | + try { |
| 183 | + lock.lock(); |
| 184 | + while (count % 3 != this.threadNo) { |
| 185 | + if (count >= 101) { |
| 186 | + break; |
| 187 | + } |
| 188 | + try { |
| 189 | + c.await(); |
| 190 | + } catch (InterruptedException e) { |
| 191 | + e.printStackTrace(); |
| 192 | + } |
| 193 | + } |
| 194 | + |
| 195 | + if (count >= 101) { |
| 196 | + break; |
| 197 | + } |
| 198 | + System.out.println("thread-" + this.threadNo + ":" + count); |
| 199 | + count++; |
| 200 | + |
| 201 | + c.signalAll(); |
| 202 | + |
| 203 | + } finally { |
| 204 | + lock.unlock(); |
| 205 | + } |
| 206 | + } |
| 207 | + } |
| 208 | +} |
| 209 | +``` |
| 210 | + |
| 211 | +`具体代码实现:` |
| 212 | + |
| 213 | +参见:[code](https://github.com/joyang1/JavaInterview/blob/master/codeinterview/src/main/java/cn/tommyyang/multithread/OrderPrintNum.java) |
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