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寻找旋转排序数组中的最小值
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# -*- coding: utf-8 -*-
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class Solution:
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# @param num: a rotated sorted array
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# @return: the minimum number in the array
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def findMin(self, num):
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# write your code here
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if len(num) == 1:
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return num[0]
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low = 1
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high = len(num) - 1
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while low < high:
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mid = (low + high) / 2
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if (num[mid] < num[mid - 1]) and (num[mid] < num[mid + 1]):
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return num[mid]
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elif num[mid] > num[0]:
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low += 1
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else:
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high -= 1
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return min(num[0], num[-1])

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