#!/usr/bin/python -tt

# Copyright 2010 Google Inc.

# Licensed under the Apache License, Version 2.0

# http://www.apache.org/licenses/LICENSE-2.0

# Google's Python Class

# http://code.google.com/edu/languages/google-python-class/

"""Wordcount exercise

Google's Python class

The main() below is already defined and complete. It calls print_words()

and print_top() functions which you write.

1. For the --count flag, implement a print_words(filename) function that counts

how often each word appears in the text and prints:

word1 count1

word2 count2

...

Print the above list in order sorted by word (python will sort punctuation to

come before letters -- that's fine). Store all the words as lowercase,

so 'The' and 'the' count as the same word.

2. For the --topcount flag, implement a print_top(filename) which is similar

to print_words() but which prints just the top 20 most common words sorted

so the most common word is first, then the next most common, and so on.

Use str.split() (no arguments) to split on all whitespace.

Workflow: don't build the whole program at once. Get it to an intermediate

milestone and print your data structure and sys.exit(0).

When that's working, try for the next milestone.

Optional: define a helper function to avoid code duplication inside

print_words() and print_top().

"""

import sys

def Cat(filename):

f = open(filename, 'r')

for line in f:

print line,

f.close()

# +++your code here+++

# Define print_words(filename) and print_top(filename) functions.

# You could write a helper utility function that reads a file

# and builds and returns a word/count dict for it.

# Then print_words() and print_top() can just call the utility function.

###

def readFile(filename):

f = open(filename, 'r')

dicA = {}

listText = f.read().split()

for i in listText:

if dicA.has_key(i):

dicA[i] = dicA.get(i) + 1

else:

dicA[i] = 1

f.close()

return dicA

def print_words(filename):

dicB = readFile(filename)

for i in sorted(dicB.keys()):

print i,dicB.get(i)

#return last element of a tuple

def get_key(tuple):

return tuple[-1]

def print_top(filename):

dicC = readFile(filename)

listA = dicC.items()

listB = sorted(listA,key=get_key,reverse=True)

if len(listB) >= 20:

for i in range(0,20):

print listB[i][0], listB[i][1]

else:

print "Text less than 20 words"

# This basic command line argument parsing code is provided and

# calls the print_words() and print_top() functions which you must define.

def main():

if len(sys.argv) != 3:

print 'usage: ./wordcount.py {--count | --topcount} file'

sys.exit(1)

option = sys.argv[1]

filename = sys.argv[2]

if option == '--count':

print_words(filename)

elif option == '--topcount':

print_top(filename)

else:

print 'unknown option: ' + option

sys.exit(1)

if __name__ == '__main__':

main()