# s1 = {10, 20, 30}

# print(s1)

# s2 = set([20, 30, 40]) #create a set out of list

# print(s2)

# s3 = {} #this will create an empty disctionary

# print(type(s3))

# s4 = set() #this will create empty set

# print(type(s4))

# print(s4)

# #insetion in set

# s = {10, 20}

# s.add(30)

# print(s)

# s.add(30) #here it will not add 30 as this value already present in the set, and set will not have duplicate value

# print(s)

# s.update([40,50])

# print(s)

# s.update({60, 70}, [80, 90])

# print(s)

# #removal operation on set

# s = {10, 30, 20, 40}

# print(s)

# s.discard(30) #delete 30, if item is not present in set it will not perform any action

# print(s)

# s.remove(20) #raise an error if the item is not in set

# print(s)

# s.clear() #everything will remove from collections you will have empty set

# print(s)

# s.add(50)

# print(s)

# del s #it will delte the object of set

# #print(s)

# s = {10, 20, 30}

# print (len(s))

# print (20 in s)

# print(50 in s)

###############################################################################################

# s1 = {2, 4, 6, 8}

# s2 = {3, 6, 9}

# print(s1 | s2) #union of two set

# setun = s1.union(s2)

# print(setun)

# print (s1 & s2) #intersection of two set

# setin = s1.intersection(s2)

# print(setin)

# print (s1 - s2)

# setdiff = s1.difference(s2)

# print(setdiff)

# print (s1 ^ s2) #symmitric difference element present in both the set but not common

# setsym = s1.symmetric_difference(s2)

# print ( setsym)

###############################################################################################

s1 = {2, 4, 6, 8}

s2 = {4, 8}

print(s1.isdisjoint(s2)) #boolean value -> true if no common element in set --> false if there is a common element

print(s1 <= s2) #issubset operator s1 is subset of s2 or not

print(s1.issubset(s2))

print(s1 < s2) #if s1 is proper set of s2 or not IF true the s1 should have less element and all the elementof s1 should present in s2

print(s1 >= s2) #if s1 is superset of s2 or not IF true the s1 should have all the element present in s2

print(s1.issuperset(s2))

print(s1>s2) #propersuperset