- Function pointers in C
- Pointers to functions
- Function pointers in C/C++
- Why pointers to functions?
- Everything you need to know about pointers in C
- What are function pointers and how to use them
- What does a function pointer exactly hold
- Where does a function pointer point to in the virtual memory
Function pointers are variables that hold the address of a function in memory. They allow you to pass functions as arguments to other functions, or to store functions in arrays or structures.
Here's an example of a function pointer declaration:
int (*myFunc)(int, int);This declares a function pointer called myFunc that takes two int arguments and returns an int.
To use a function pointer, you need to assign it the address of a function. Here's an example:
int add(int a, int b) {
return a + b;
}
int (*myFunc)(int, int) = add;This assigns the address of the add function to myFunc.
You can then call the function using the pointer, like this:
int result = myFunc(4, 5); // result will be 9Function pointers can also be used with function pointers in arrays or structures. Here's an example of a function pointer array:
int add(int a, int b) {
return a + b;
}
int subtract(int a, int b) {
return a - b;
}
int multiply(int a, int b) {
return a * b;
}
int (*mathFuncs[3])(int, int) = { add, subtract, multiply };This declares an array called mathFuncs that holds three function pointers to the add, subtract, and multiply functions.
You can then call the functions using the pointers in the array, like this:
int result1 = mathFuncs[0](4, 5); // result1 will be 9
int result2 = mathFuncs[1](4, 5); // result2 will be -1
int result3 = mathFuncs[2](4, 5); // result3 will be 20Function pointers hold the address of a function in virtual memory. When you call a function through a function pointer, the program looks up the function's address in memory and jumps to that location to execute the function.
0. What's my name
#include "function_pointers.h"
#include <stdio.h>
/**
* print_name_as_is - prints a name as is
* @name: name to print
*
* Return: void
*/
void print_name_as_is(char *name)
{
printf("Hello, my name is %s\n", name);
}
/**
* print_name_uppercase - prints a name in uppercase
* @name: name to print
*
* Return: void
*/
void print_name_uppercase(char *name)
{
int i;
printf("Hello, my uppercase name is ");
for (i = 0; name[i]; i++)
{
if (name[i] >= 'a' && name[i] <= 'z')
printf("%c", name[i] - 32);
else
printf("%c", name[i]);
}
printf("\n");
}
/**
* main - check the code
* Return: Always 0.
*/
int main(void)
{
print_name("Bob", print_name_as_is);
print_name("Bob Dylan", print_name_uppercase);
printf("\n");
return (0);
}Compiled with:
gcc -Wall -pedantic -Werror -Wextra 0-main.c 0-print_name.c -o 0-print_nameOutput:$ ./0-print_name Hello, my name is Bob Hello, my uppercase name is BOB DYLAN
1. If you spend too much time thinking about a thing, you'll never get it done
#include "function_pointers.h"
#include <stdio.h>
/**
* print_elem - prints an integer
* @elem: integer to print
*
* Return: void
*/
void print_elem(int elem)
{
printf("%d\n", elem);
}
/**
* print_elem_hex - prints an integer in hexadecimal
* @elem: integer to print
*
* Return: void
*/
void print_elem_hex(int elem)
{
printf("0x%x\n", elem);
}
/**
* main - check the code
* Return: Always 0.
*/
int main(void)
{
int array[5] = {0, 98, 402, 1024, 4096};
array_iterator(array, 5, print_elem);
printf("\n");
array_iterator(array, 5, print_elem_hex);
return (0);
}Compiled with:
gcc -Wall -pedantic -Werror -Wextra 1-main.c 1-array_iterator.c -o 1-array_iteratorOutput:$ ./1-array_iterator 0 98 402 1024 4096 0x0 0x62 0x192 0x400 0x1000
2. To hell with circumstances; I create opportunities
#include "function_pointers.h"
#include <stdio.h>
/**
* is_98 - checks if a number is equal to 98
* @elem: integer to check
*
* Return: 1 if true, 0 otherwise
*/
int is_98(int elem)
{
return (elem == 98);
}
/**
* is_strictly_positive - checks if a number is greater than 0
* @elem: integer to check
*
* Return: 1 if true, 0 otherwise
*/
int is_strictly_positive(int elem)
{
return (elem > 0);
}
/**
* main - check the code
* Return: Always 0.
*/
int main(void)
{
int array[5] = {0, 98, 402, 1024, 4096};
int index;
index = int_index(array, 5, is_98);
printf("%d\n", index);
index = int_index(array, 5, is_strictly_positive);
printf("%d\n", index);
index = int_index(array, 5, NULL);
printf("%d\n", index);
return (0);
}Compiled with:
gcc -Wall -pedantic -Werror -Wextra 2-main.c 2-int_index.c -o 2-int_indexOutput:$ ./2-int_index 1 2 -1
3. A goal is not always meant to be reached, it often serves simply as something to aim at
Write a program that performs simple operations.
- You are allowed to use the standard library
- Usage:
calc num1 operator num2 - You can assume
num1andnum2are integers, so use theatoifunction to convert them from the string input toint operatoris one of the following:+: addition-: subtraction*: multiplication/: division%: modulo
- The program prints the result of the operation, followed by a new line
- You can assume that the result of all operations can be stored in an
int - If the number of arguments is wrong, print
Error, followed by a new line, and exit with the status98 - If the
operatoris none of the above, printError, followed by a new line, and exit with the status99 - If the user tries to divide (
/or%) by0, printError, followed by a new line, and exit with the status100
This task requires that you create four different files.
3-calc.hshould contain all the function prototypes and data structures used by the program. You can only use this structure:
/**
* struct op - Struct op
*
* @op: The operator
* @f: The function associated
*/
typedef struct op
{
char *op;
int (*f)(int a, int b);
} op_t;-
3-op_functions.cshould contain the 5 following functions (not more):op_addthat returns the sum of a and b. (prototype:int op_add(int a, int b);)op_subthat returns the difference of a and b. (prototype:int op_sub(int a, int b);)op_multhat returns the product of a and b. (prototype:int op_mul(int a, int b);)op_divthat returns the result of the division of a by b. (prototype:int op_div(int a, int b);)op_modthat returns the remainder of the division of a by b. (prototype:int op_mod(int a, int b);)
-
3-get_op_func.cshould contain the function that selects the correct function to perform the operation asked by the user. You’re not allowed to declare any other function.- Prototype:
int (*get_op_func(char *s))(int, int);
- Where
sis the operator passed as argument to the program. - Your function returns a pointer to the function that corresponds to the operator given as a parameter. Example:
get_op_func("+")should return a pointer to the functionop_add. - You are not allowed to use
else,switch,case,goto, or ternary operator (?:). - You are not allowed to use
forordo ... whileloops. - You are not allowed to use more than one
ifstatement in your code. - You are not allowed to use more than one
whileloop in your code. - If
sdoes not match any of the 5 expected operators (+,-,*,/,%), returnNULL. - You are only allowed to declare these two variables in this function:
op_t ops[] = { {"+", op_add}, {"-", op_sub}, {"*", op_mul}, {"/", op_div}, {"%", op_mod}, {NULL, NULL} }; int i;
- Prototype:
-
3-main.cshould contain yourmainfunction only.- You are not allowed to code any other function than
mainin the file3-main.c. - You are not allowed to directly call
op_add,op_sub,op_mul,op_divandop_modfrom the file3-main.c. - You have to use
atoito convert arguments toint. - You are not allowed to use any kind of loop (
for,do ... while,while, etc.). - You are allowed a maximum of 3
ifstatements in your code.
- You are not allowed to code any other function than
Compiled with:
gcc -Wall -pedantic -Werror -Wextra -std=gnu89 3-main.c 3-op_functions.c 3-get_op_func.c -o calc
Output:
$ ./calc 1 + 1 2 $ ./calc 1024 '*' 98 100352 $ ./calc 1024 '/' 98 10 $ ./calc 1024 '%' 98 38 $ ./calc 1024 '+' 98 1122 $ ./calc 1024 '-' 98 926 $ ./calc 1024 'a' 98 Error $ ./calc 1024 '+' 98 98 Error $
4. Once an idea has taken hold of the brain it's almost impossible to eradicate
Write a program that prints the opcodes of its own main function.
- Usage:
./main number_of_bytes - Output format:
- the opcodes should be printed in hexadecimal, lowercase
- each opcode is two char long
- listing ends with a new line
- see example
- You are allowed to use
printfandatoi - You have to use
atoito convert the argument to anint - If the number of arguments is not the correct one, print
Error, followed by a new line, and exit with the status1 - If the number of bytes is negative, print
Error, followed by a new line, and exit with the status2 - You do not have to compile with any flags
Note: if you want to translate your opcodes to assembly instructions, you can use, for instance udcli.
Output:
$ ./main 21
55 48 89 e5 48 83 ec 30 89 7d dc 48 89 75 d0 83 7d dc 02 74 14
$ objdump -d -j.text -M intel main
[...]
00000000004005f6 <main>:
4005f6: 55 push rbp
4005f7: 48 89 e5 mov rbp,rsp
4005fa: 48 83 ec 30 sub rsp,0x30
4005fe: 89 7d dc mov DWORD PTR [rbp-0x24],edi
400601: 48 89 75 d0 mov QWORD PTR [rbp-0x30],rsi
400605: 83 7d dc 02 cmp DWORD PTR [rbp-0x24],0x2
400609: 74 14 je 40061f <main+0x29>
[...]
$ ./main 21 | udcli -64 -x -o 4005f6
00000000004005f6 55 push rbp
00000000004005f7 4889e5 mov rbp, rsp
00000000004005fa 4883ec30 sub rsp, 0x30
00000000004005fe 897ddc mov [rbp-0x24], edi
0000000000400601 488975d0 mov [rbp-0x30], rsi
0000000000400605 837ddc02 cmp dword [rbp-0x24], 0x2
0000000000400609 7414 jz 0x40061f
[...]
$Note 0:
jeis equivalent tojzNote 1: depending on how you write yourmainfunction, and on which machine you compile your program, the opcodes (and by extension the assembly code) might be different than the above example