//Given an array length 1 or more of ints, return the difference between the largest and smallest values in the array. Note: the built-in Math.min(v1, v2) and Math.max(v1, v2) methods return the smaller or larger of two values.

//

//bigDiff([10, 3, 5, 6]) → 7

//bigDiff([7, 2, 10, 9]) → 8

//bigDiff([2, 10, 7, 2]) → 8

public int bigDiff(int[] nums) {

if (nums.length==0)

return 0;

int min=nums[0];

int max=nums[0];

for (int count=0;count<nums.length;count++){

max=Math.max(max,nums[count]);

min=Math.min(min,nums[count]);

}

return max-min;

}