/*

The sum of the squares of the first ten natural numbers is,

1^2 + 2^2 + ... + 10^2 = 385

The square of the sum of the first ten natural numbers is,

(1 + 2 + ... + 10)^2 = 55^2 = 3025

Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 − 385 = 2640.

Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.

*/

public class problem06 {

public static void main(String args[]) {

double difference = squareOfSum() - sumOfSquares();

System.out.println(difference);

}

public static double sumOfSquares() {

double sum=0;

for (double i=1; i<=100; i++) {

sum += i*i;

}

return sum;

}

public static double squareOfSum() {

double square=0;

for (double i=1; i<=100; i++) {

square += i;

}

return square*square;

}

}