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LeetCode79.java
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85 lines (68 loc) · 2.67 KB
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package LeetCode;
public class LeetCode79 {
// https://leetcode-cn.com/problems/word-search/description/
/// 回溯法
/// 时间复杂度: O(m*n*m*n)
/// 空间复杂度: O(m*n)
// 左,上,右,下移动
private int d[][] = {{-1, 0}, {0, 1}, {1, 0}, {0, -1}};
private int m, n;
private boolean[][] visited;
public boolean exist(char[][] board, String word) {
if (board == null || word == null)
throw new IllegalArgumentException("board or word can not be null!");
m = board.length;
if (m == 0)
throw new IllegalArgumentException("board can not be empty.");
n = board[0].length;
if (n == 0)
throw new IllegalArgumentException("board can not be empty.");
visited = new boolean[m][n];
for (int i = 0; i < m; i++)
for (int j = 0; j < n; j++)
if (searchWord(board, word, 0, i, j))
return true;
return false;
}
// 判断坐标是否在区域内
private boolean inArea(int x, int y) {
return x >= 0 && x < m && y >= 0 && y < n;
}
// 从board[startx][starty]开始, 寻找word[index...word.size())
private boolean searchWord(char[][] board, String word, int index,
int startx, int starty) {
//assert(inArea(startx,starty));
if (index == word.length() - 1)
return board[startx][starty] == word.charAt(index);
if (board[startx][starty] == word.charAt(index)) {
visited[startx][starty] = true;
// 从startx, starty出发,向四个方向寻
for (int i = 0; i < 4; i++) {
int newx = startx + d[i][0];
int newy = starty + d[i][1];
if (inArea(newx, newy) && !visited[newx][newy] &&
searchWord(board, word, index + 1, newx, newy))
return true;
}
visited[startx][starty] = false;
}
return false;
}
public static void main(String args[]) {
char[][] b1 = {{'A', 'B', 'C', 'E'},
{'S', 'F', 'C', 'S'},
{'A', 'D', 'E', 'E'}};
String words[] = {"ABCCED", "SEE", "ABCB"};
for (int i = 0; i < words.length; i++)
if ((new LeetCode79()).exist(b1, words[i]))
System.out.println("found " + words[i]);
else
System.out.println("can not found " + words[i]);
// ---
char[][] b2 = {{'A'}};
if ((new LeetCode79()).exist(b2, "AB"))
System.out.println("found AB");
else
System.out.println("can not found AB");
}
}