### Printing Patterns in Python ###

Q) Create a 4 # in 4 Rows like below pattern

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#Correct one

for i in range(4):

for j in range(4):

print("#", end="")

print()

###The below one is another way

for j in range (4):

print("#", end="")

print()

for j in range (4):

print("#", end="")

print()

for j in range (4):

print("#", end="")

print()

for j in range (4):

print("#", end="")

print()

### to print below pattern

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# telusko code

for i in range(4):

for j in range(i+1):

print("#", end="")

print()

#Another own code example for above pattern

for i in range(1,5):

for j in range(i):

print("#", end="")

print()

### to print below pattern

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#

# Telusko

for i in range(4):

for j in range(4-i):

print("#", end="")

print()

#own

for j in range(4):

for i in range(4-j):

print("#", end="")

print()

### To apply "continue", "break" for above patterns

for i in range(4):

if i==2:

continue

for j in range(4):

print("#",end="")

print()

# here we have given break statement inside of the nested for loop hence when i==2 applied inner loop skip the 2### program excution has stopped.

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for i in range(4):

for j in range(4):

if i==2:

break

print("#",end="")

print()

print("This is end")

# here we have given break statement out side of the nested for loop hence when i==2 applied end the statement and program excution has stopped.

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###

for j in range(4):

if i==2:

break # here we have given break statement out side of the nested for loop hence when i==2 applied end the statement and program excution has stopped.

for i in range(4-j):

print("#", end="")

print()

for j in range(1,5):

for i in range(j):

print("*", end="")

if i==2:

break

print()