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test_re.py
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100 lines (86 loc) · 2.39 KB
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# coding=utf-8
__author__ = 'zhanghe'
import re
import json
test_html = '''<dl class="lineDl">
<dt>工作年限：</dt>
<dd>
<div class="inptext_fl ">应届毕业生</div>
<input type="hidden" id="WorkYear" value="2"/>
</dd>
</dl>
<dl class="lineDl">
<dt>居住地：</dt>
<dd>
<div class="inptext_fl ">清远</div>
</dd>
</dl>
<dl class="lineDl">
<dt>求职状态：</dt>
<dd>
<div class="inptext_fl ">目前正在找工作</div>
</dd>
</dl>
<dl class="lineDl">
<dt>身高：</dt>
<dd class="dd_textW">
<div class="inptext_fl ">180cm </div>
</dd>
<dt>婚姻状况：</dt>
<dd>
<div class="inptext_fl "> </div>
</dd>
</dl>'''
def re_html(html):
"""
通过正则表达式获取关键数据
将两个有序的列表组合为无序的字典
:param html:
:return:
"""
reg_dt = r'<dt>(.+?)：</dt>'
reg_dd = r'<div class="inptext_fl ">(.+?)</div>'
dt = re.compile(reg_dt)
dd = re.compile(reg_dd)
dt_list = re.findall(dt, html)
dd_list = re.findall(dd, html)
zip_list = zip(dt_list, dd_list)
html_dict = dict((name, value) for name, value in zip_list)
return json.dumps(html_dict, ensure_ascii=False, indent=4)
def get_email(html=None):
"""
从文本中提取email
"""
if html is None:
return []
email_rule = r'[^\_\@\s\W][\w\_\-\.]{1,}\@(?:[^\s\.]{1,}\.){1,}(?:[a-z]{2,4}\.?){1,2}'
email_list = re.compile(email_rule, re.S).findall(html)
# print json.dumps(email_list, ensure_ascii=False, indent=4)
# email_list_new = []
# for item in email_list:
# email_list_new.append(item.lower())
# return email_list_new
return [item.lower() for item in email_list]
if __name__ == '__main__':
# print re_html(test_html)
html_test = '''邮箱：[email protected] [email protected] [email protected] [email protected] [email protected] @[email protected] @[email protected] [email protected] 地址：上海市'''
email_result = get_email(html_test)
print json.dumps(email_result, ensure_ascii=False, indent=4)
"""
测试结果
[
]
"""
"""
(?:pattern)
匹配 pattern 但不获取匹配结果
例如， 'industr(?:y|ies) 就是一个比 'industry|industries' 更简略的表达式。
"""