Symmetric matrices are matrices that have the property:
\[A = A^T \tag{1}\]Skew-symmetric matrices on the other hand have a related but slightly different property:
\[A = -A^T \tag{2}\]An interesting property that emerges as a consequence of this relationship, is that if a matrix \(A\) is skew-symmetric, then its inverse, \(A^{-1}\), is also skew-symmetric; i.e:
\[A^{-1} = -(A^{-1})^{T} \tag{3}\]We can prove this from the above equation, and a familar property which is:
If \(A\) is invertible, then (I’ll show this proof in a future post):
\[(A^{-1})^{T} = (A^{T})^{-1} \tag{4}\]Given this relationship, we can use Eq. \((4)\) in the RHS of Eq. \((3)\) to get:
\[-(A^{-1})^{T} = -(A^{T})^{-1}\tag{5}\]And, since we established in Eq. \((1)\) that \(A\) is skew-symmetric already we have:
\[-(A^{-1})^{T} = -(A^{T})^{-1} = -(-A)^{-1} = A^{-1}\tag{6}\]Therefore proving Eq. \((3)\)
I found this StackOverflow answer helpful [1] while recollecting these topics.
-Sarthak
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