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SQLServerCentral Article

How to Add a New Shared Disk to a WSFC as a SQL Resource

  • Article

Adding a new shared disk to Windows Server failover Cluster is not a complex process but special care must be taken when you want to use the new disk for any existing SQL Instance. In this article, we will show you all the required steps to add the disk to WSFC and then to properly assign it to an existing SQL role in the WSFC.

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2024-09-16

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SQLServerCentral Article

A Step by Step Guide to the Availability Group (AG) Listener

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Availability databases hosted on SQL Server Always On Availability Groups (AG) can be connected using a unique Virtual Network Name (VNN), called the Availability Group Listener. When an Availability Group is enabled, clients can connect to databases in both primary and secondary replicas without explicitly specifying the SQL Server instance name. You don’t even need […]

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2021-05-17

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SQLServerCentral Article

Fixing "Login failed for user" error in SQL Server

  • Article

In this article, I am going to explain fixing a problem related login failure error with SQL Server. The Problem One of the common error in the SQL Server error log is "Login failed for user 'DomainName\ServerName$'. Reason: Could not find a login matching the name provided. [CLIENT: <local machine>]". Even though it says that […]

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2025-12-31 (first published: )

54,565 reads

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Fun with JSON II

By Steve Jones - SSC Editor

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Changing Data Types

By Steve Jones - SSC Editor

Comments posted to this topic are about the item Changing Data Types

Answering Questions On Dropped Columns

By Cláudio Silva

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Question of the Day

Fun with JSON II

I have some data in a table:

CREATE TABLE #test_data
(
    id INT PRIMARY KEY,
    name VARCHAR(100),
    birth_date DATE
);

-- Step 2: Insert rows  
INSERT INTO #test_data
VALUES
(1, 'Olivia', '2025-01-05'),
(2, 'Emma', '2025-03-02'),
(3, 'Liam', '2025-11-15'),
(4, 'Noah', '2025-12-22');
If I run this query, how many rows are returned?
SELECT t1.[key] AS row,
       t2.*
FROM OPENJSON(
     (
         SELECT t.* FROM #test_data AS t FOR JSON PATH
     )
             ) t1
    CROSS APPLY OPENJSON(t1.value) t2;

See possible answers