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67 changes: 64 additions & 3 deletions 2-exercises/task.md
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Expand Up @@ -7,6 +7,7 @@ In this homework, you are going to work with an ecommerce database. In this data
Below you will find a set of tasks for you to complete to set up a database for an e-commerce app.

To submit this homework write the correct commands for each question here:

```sql


Expand Down Expand Up @@ -35,16 +36,76 @@ Open the file `cyf_ecommerce.sql` in VSCode and examine the SQL code. Take a pie
Once you understand the database that you are going to work with, solve the following challenge by writing SQL queries using everything you learned about SQL:

1. Retrieve all the customers' names and addresses who live in the United States

select name, address from customers where country = 'United States';

2. Retrieve all the customers in ascending name sequence

SELECT \* from customers order by name asc;

3. Retrieve all the products whose name contains the word `socks`

select \* from products where product_name like '%socks%';

4. Retrieve all the products which cost more than 100 showing product id, name, unit price and supplier id.

select p.id,p.product_name,p_a.unit_price,p_a.supp_id from products p join product_availability p_a on (p.id = p_a.prod_id) where p_a.unit_price > 100;

5. Retrieve the 5 most expensive products
6. Retrieve all the products with their corresponding suppliers. The result should only contain the columns `product_name`, `unit_price` and `supplier_name`

SELECT \* from products join product_availability on products.id = product_availability.prod_id order by unit_price desc limit 5;

6. Retrieve all the products with their corresponding
suppliers. The result should only contain the columns `product_name`, `unit_price` and `supplier_name`

select p.product_name, p_a.unit_price,s.supplier_name from products p join product_availability p_a on (p.id = p_a.prod_id) join suppliers s on (s.id = p_a.supp_id);

7. Retrieve all the products sold by suppliers based in the United Kingdom. The result should only contain the columns `product_name` and `supplier_name`.
8. Retrieve all orders, including order items, from customer ID `1`. Include order id, reference, date and total cost (calculated as quantity * unit price).

select p.product_name , s.supplier_name
from products p join product_availability p_a on (p_a.prod_id = p.id) join suppliers s on (s.id = p_a.supp_id) where s.country = 'United Kingdom';

8. Retrieve all orders, including order items, from customer ID `1`. Include order id, reference, date and total cost (calculated as quantity \* unit price).

select o.id , o.order_reference , o.order_date , (o_i.quantity \* p_a.unit_price) as total_cost
from orders o join order_items o_i on (o.id = o_i.order_id)
join product_availability p_a on (p_a.prod_id = o_i.product_id) where o.customer_id = 1;

9. Retrieve all orders, including order items, from customer named `Hope Crosby`

select o.id, o.order_reference , o_i.product_id, p.product_name , o_i.quantity from orders o
join order_items o_i on (o.id = o_i.order_id) join products p on (o_i.product_id = p.id)
join customers on (customers.id = o.customer_id)
where customers.name='Hope Crosby';

10. Retrieve all the products in the order `ORD006`. The result should only contain the columns `product_name`, `unit_price` and `quantity`.

select p.product_name , p_a.unit_price , o_i.quantity from orders o
join order_items o_i on (o_i.order_id = o.id)
join products p on (o_i.product_id = p.id)
join product_availability p_a on (p_a.prod_id = o_i.product_id) where o.order_reference = 'ORD006';

11. Retrieve all the products with their supplier for all orders of all customers. The result should only contain the columns `name` (from customer), `order_reference`, `order_date`, `product_name`, `supplier_name` and `quantity`.

select c.name , o.order_reference, o.order_date, p.product_name, s.supplier_name, o_i.quantity from customers c
join orders o on (c.id = o.customer_id)
join order_items o_i on (o.id = o_i.order_id)
join products p on (p.id = o_i.product_id)
join suppliers s on (o_i.supplier_id = s.id);

12. Retrieve the names of all customers who bought a product from a supplier based in China.
13. List all orders giving customer name, order reference, order date and order total amount (quantity * unit price) in descending order of total.

select distinct c.name from customers c
join orders on (orders.customer_id = c.id)
join order_items on (order_items.order_id = orders.id)
join suppliers on (suppliers.id = order_items.supplier_id)
where suppliers.country = 'China';

13. List all orders giving customer name, order reference, order date and order total amount (quantity \* unit price) in descending order of total.

SELECT customers.name,orders.order_reference,orders.order_date,(quantity \* unit_price) AS total_amount
FROM customers
INNER JOIN orders ON orders.customer_id = customers.id
INNER JOIN order_items ON order_items.order_id = orders.id
INNER JOIN product_availability ON order_items.product_id = product_availability.prod_id
ORDER BY total_amount DESC;
21 changes: 21 additions & 0 deletions 3-projects/.gitignore
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@@ -0,0 +1,21 @@

/node_modules
/.pnp
.pnp.js

# testing
/coverage

# production
/build

# misc
.DS_Store
.env.local
.env.development.local
.env.test.local
.env.production.local

npm-debug.log*
yarn-debug.log*
yarn-error.log*
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