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Assignment one #1

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73a4a3b
Completed SQL Assignment 1 for submission.
abeerkhe Aug 10, 2025
4bf8653
Added my Assignment 1 data model.
abeerkhe Aug 10, 2025
0b4ece2
Making updates to SQL Assignment 1 as per grader feedback. ß
abeerkhe Aug 15, 2025
bfb5a68
Submission for Assignment 2. Late Submission
abeerkhe Aug 21, 2025
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68 changes: 62 additions & 6 deletions 02_activities/assignments/assignment1.sql
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Expand Up @@ -5,17 +5,24 @@
--SELECT
/* 1. Write a query that returns everything in the customer table. */


SELECT *
FROM customer

/* 2. Write a query that displays all of the columns and 10 rows from the cus- tomer table,
sorted by customer_last_name, then customer_first_ name. */


SELECT *
FROM customer
ORDER BY customer_last_name, customer_first_name
LIMIT 10

--WHERE
/* 1. Write a query that returns all customer purchases of product IDs 4 and 9. */
-- option 1

SELECT *
FROM customer_purchases
WHERE product_id=4 OR product_id=9

-- option 2

Expand All @@ -26,8 +33,12 @@ filtered by vendor IDs between 8 and 10 (inclusive) using either:
1. two conditions using AND
2. one condition using BETWEEN
*/

-- option 1

SELECT *, (quantity * cost_to_customer_per_qty) AS price
FROM customer_purchases
WHERE vendor_id BETWEEN 8 AND 10

-- option 2

Expand All @@ -39,19 +50,43 @@ Using the product table, write a query that outputs the product_id and product_n
columns and add a column called prod_qty_type_condensed that displays the word “unit”
if the product_qty_type is “unit,” and otherwise displays the word “bulk.” */

SELECT product_id,
product_name,
CASE product_qty_type
WHEN 'unit'
THEN 'unit'
ELSE 'bulk'
END AS product_qty_type_condensed
FROM product


/* 2. We want to flag all of the different types of pepper products that are sold at the market.
add a column to the previous query called pepper_flag that outputs a 1 if the product_name
contains the word “pepper” (regardless of capitalization), and otherwise outputs 0. */


SELECT product_id,
product_name,
CASE product_qty_type
WHEN 'unit'
THEN 'unit'
ELSE 'bulk'
END AS product_qty_type_condesed,
CASE
WHEN product_name LIKE '%pepper%'
THEN '1'
ELSE '0'
END AS pepper_flag
FROM product

--JOIN
/* 1. Write a query that INNER JOINs the vendor table to the vendor_booth_assignments table on the
vendor_id field they both have in common, and sorts the result by vendor_name, then market_date. */


SELECT *
FROM vendor_booth_assignments AS vb
INNER JOIN vendor as v
ON vb.vendor_id = v.vendor_id
ORDER BY vendor_name, market_date


/* SECTION 3 */
Expand All @@ -60,14 +95,23 @@ vendor_id field they both have in common, and sorts the result by vendor_name, t
/* 1. Write a query that determines how many times each vendor has rented a booth
at the farmer’s market by counting the vendor booth assignments per vendor_id. */


SELECT vendor_id, COUNT (vendor_id)
FROM vendor_booth_assignments
GROUP BY vendor_id

/* 2. The Farmer’s Market Customer Appreciation Committee wants to give a bumper
sticker to everyone who has ever spent more than $2000 at the market. Write a query that generates a list
of customers for them to give stickers to, sorted by last name, then first name.

HINT: This query requires you to join two tables, use an aggregate function, and use the HAVING keyword. */

SELECT *, SUM((cp.quantity * cp.cost_to_customer_per_qty)) AS price
FROM customer as c
INNER JOIN customer_purchases as cp
ON c.customer_id = cp.customer_id
GROUP BY c.customer_id
HAVING price>2000
ORDER BY c.customer_last_name, c.customer_first_name


--Temp Table
Expand All @@ -82,6 +126,13 @@ When inserting the new vendor, you need to appropriately align the columns to be
VALUES(col1,col2,col3,col4,col5)
*/

DROP TABLE IF EXISTS new_vendor;

CREATE TEMP TABLE new_vendor AS
SELECT * FROM vendor;

INSERT INTO new_vendor (vendor_id, vendor_name, vendor_type, vendor_owner_first_name, vendor_owner_last_name)
VALUES(10, 'Thomass Superfood Store', 'Fresh Focused Store', 'Thomas', 'Rosenthal');


-- Date
Expand All @@ -90,11 +141,16 @@ VALUES(col1,col2,col3,col4,col5)
HINT: you might need to search for strfrtime modifers sqlite on the web to know what the modifers for month
and year are! */


SELECT customer_id, strftime('%m', market_date) AS month, strftime('%Y', market_date) AS year
FROM customer_purchases

/* 2. Using the previous query as a base, determine how much money each customer spent in April 2022.
Remember that money spent is quantity*cost_to_customer_per_qty.

HINTS: you will need to AGGREGATE, GROUP BY, and filter...
but remember, STRFTIME returns a STRING for your WHERE statement!! */

SELECT customer_id, SUM(quantity*cost_to_customer_per_qty) AS price, strftime('%m', market_date) AS month, strftime('%Y', market_date) AS year
FROM customer_purchases
WHERE month='04' AND year='2022'
GROUP BY customer_id
158 changes: 148 additions & 10 deletions 02_activities/assignments/assignment2.sql
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Expand Up @@ -20,7 +20,11 @@ The `||` values concatenate the columns into strings.
Edit the appropriate columns -- you're making two edits -- and the NULL rows will be fixed.
All the other rows will remain the same.) */


SELECT
product_name || ', ' || COALESCE(product_size, '') || ' (' || COALESCE(product_qty_type, 'unit') || ')'
AS product_description
FROM
product;

--Windowed Functions
/* 1. Write a query that selects from the customer_purchases table and numbers each customer’s
Expand All @@ -32,18 +36,61 @@ each new market date for each customer, or select only the unique market dates p
(without purchase details) and number those visits.
HINT: One of these approaches uses ROW_NUMBER() and one uses DENSE_RANK(). */


SELECT
customer_id,
DENSE_RANK() OVER (PARTITION BY customer_id ORDER BY market_date) AS visit_number,
market_date
FROM
customer_purchases
ORDER BY
customer_id,
market_date;

/* 2. Reverse the numbering of the query from a part so each customer’s most recent visit is labeled 1,
then write another query that uses this one as a subquery (or temp table) and filters the results to
only the customer’s most recent visit. */


SELECT customer_id, visit_number, market_date
FROM
(
SELECT
customer_id,
DENSE_RANK() OVER (PARTITION BY customer_id ORDER BY market_date DESC) AS visit_number,
market_date
FROM
customer_purchases
ORDER BY
customer_id,
market_date DESC
)
WHERE
visit_number LIKE '1'
GROUP BY
customer_id,
visit_number;

/* 3. Using a COUNT() window function, include a value along with each row of the
customer_purchases table that indicates how many different times that customer has purchased that product_id. */

/*The function below adds a "product_purchase_count" value to each row of the customer_purchases table, such
that each unique purchase shows the total count of how many times that item has been purchased.
For an aggregate view of product and number of times purchased with one row per product,
the SELECt statement would exclude unique purchase identifiers (i.e., datetime and vendor).*/

SELECT
customer_id,
product_id,
COUNT() OVER (PARTITION BY customer_id ORDER BY product_id) AS product_purchase_count,
market_date,
vendor_id,
quantity,
cost_to_customer_per_qty,
transaction_time
FROM
customer_purchases
ORDER BY
customer_id,
product_id;

-- String manipulations
/* 1. Some product names in the product table have descriptions like "Jar" or "Organic".
Expand All @@ -57,11 +104,34 @@ Remove any trailing or leading whitespaces. Don't just use a case statement for

Hint: you might need to use INSTR(product_name,'-') to find the hyphens. INSTR will help split the column. */


SELECT product_id, product_name,
CASE
WHEN INSTR(product_name, '-') <> 0
THEN REPLACE(SUBSTR(product_name, INSTR(product_name, '-')+1, LENGTH(product_name) - INSTR(product_name, '-')), ' ', '')
ELSE NULL
END product_type,
product_size,
product_category_id,
product_qty_type
FROM
product

/* 2. Filter the query to show any product_size value that contain a number with REGEXP. */


SELECT
product_id,
product_name,
CASE
WHEN INSTR(product_name, '-') <> 0
THEN REPLACE(SUBSTR(product_name, INSTR(product_name, '-')+1, LENGTH(product_name) - INSTR(product_name, '-')), ' ', '')
ELSE NULL
END product_type,
product_size,
product_category_id,
product_qty_type

FROM product
WHERE product_size REGEXP '[0-9]'

-- UNION
/* 1. Using a UNION, write a query that displays the market dates with the highest and lowest total sales.
Expand All @@ -73,8 +143,30 @@ HINT: There are a possibly a few ways to do this query, but if you're struggling
3) Query the second temp table twice, once for the best day, once for the worst day,
with a UNION binding them. */

/* Note: This assumes multiple multiple market days did not tie for highest or lowest total
sales due to the "LIMIT 1" cuase in the FROM statements. */


SELECT
market_date,
total_sales
FROM (
SELECT market_date, SUM(cost_to_customer_per_qty*quantity) AS total_sales
FROM customer_purchases
GROUP BY market_date
ORDER BY total_sales DESC
LIMIT 1
)
UNION
SELECT
market_date,
total_sales
FROM (
SELECT market_date, SUM(cost_to_customer_per_qty*quantity) AS total_sales
FROM customer_purchases
GROUP BY market_date
ORDER BY total_sales DESC
LIMIT 1
)

/* SECTION 3 */

Expand All @@ -89,27 +181,67 @@ Think a bit about the row counts: how many distinct vendors, product names are t
How many customers are there (y).
Before your final group by you should have the product of those two queries (x*y). */


SELECT
v.vendor_name,
p.product_name,
COUNT(c.customer_id) * v_inv.original_price * 5
AS sales_by_product
FROM
vendor_inventory AS v_inv
LEFT JOIN
vendor as v
ON v_inv.vendor_id = v.vendor_id
LEFT JOIN
product AS p
ON v_inv.product_id = p.product_id
CROSS JOIN
customer AS c
GROUP BY
v.vendor_name,
p.product_name

-- INSERT
/*1. Create a new table "product_units".
This table will contain only products where the `product_qty_type = 'unit'`.
It should use all of the columns from the product table, as well as a new column for the `CURRENT_TIMESTAMP`.
Name the timestamp column `snapshot_timestamp`. */

--Delete table if exists
DROP TABLE IF EXISTS product_units;

--Create table, as per question
CREATE TABLE product_units AS
SELECT
*,
CURRENT_TIMESTAMP AS snapshot_timestamp
FROM product
WHERE product_qty_type LIKE 'unit';

--Check to ensure table works properly
SELECT * FROM product_units

/*2. Using `INSERT`, add a new row to the product_units table (with an updated timestamp).
This can be any product you desire (e.g. add another record for Apple Pie). */


INSERT INTO product_units (product_id, product_name, product_size, product_category_id, product_qty_type, snapshot_timestamp)
VALUES ('24', 'Churros', 'Medium', '3', 'unit', CURRENT_TIMESTAMP);

-- DELETE
/* 1. Delete the older record for the whatever product you added.

HINT: If you don't specify a WHERE clause, you are going to have a bad time.*/

/*I created a new product altogether in the question above, and so created a
generalized query below to apply for any product by selecting the oldest record
by its product_id.*/

DELETE FROM product_units
WHERE
product_id IN
(SELECT product_id
FROM product_units
WHERE product_name='Churros'
ORDER BY snapshot_timestamp ASC LIMIT 1)

-- UPDATE
/* 1.We want to add the current_quantity to the product_units table.
Expand All @@ -128,6 +260,12 @@ Finally, make sure you have a WHERE statement to update the right row,
you'll need to use product_units.product_id to refer to the correct row within the product_units table.
When you have all of these components, you can run the update statement. */



UPDATE product_units
SET current_quantity = COALESCE((
SELECT v_inv.quantity
FROM vendor_inventory AS v_inv
WHERE v_inv.product_id = product_units.product_id
ORDER BY v_inv.market_date DESC LIMIT 1), 0);

SELECT * FROM product_units

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