adnt01 · adnt01 · Nov 16, 2025
diff --git a/02_activities/assignments/Cohort_8/Assignment1/LogicalDataModel.pdf b/02_activities/assignments/Cohort_8/Assignment1/LogicalDataModel.pdf
diff --git a/02_activities/assignments/Cohort_8/Assignment1/assignment1.sql b/02_activities/assignments/Cohort_8/Assignment1/assignment1.sql
@@ -0,0 +1,136 @@
+/* ASSIGNMENT 1 */
+/* SECTION 2 */
+
+
+--SELECT
+/* 1. Write a query that returns everything in the customer table. */
+SELECT customer_id, customer_first_name, customer_last_name, customer_postal_code FROM customer;
+
+
+/* 2. Write a query that displays all of the columns and 10 rows from the cus- tomer table, 
+sorted by customer_last_name, then customer_first_ name. */
+SELECT customer_id, customer_first_name, customer_last_name, customer_postal_code FROM customer
+ORDER BY customer_last_name, customer_first_name
+LIMIT 10;
+
+--WHERE
+/* 1. Write a query that returns all customer purchases of product IDs 4 and 9. */
+SELECT product_id, vendor_id, market_date, customer_id, quantity, cost_to_customer_per_qty, transaction_time FROM customer_purchases
+WHERE product_id IN (4,9);
+
+
+/*2. Write a query that returns all customer purchases and a new calculated column 'price' (quantity * cost_to_customer_per_qty), 
+filtered by customer IDs between 8 and 10 (inclusive) using either:
+	1.  two conditions using AND
+	2.  one condition using BETWEEN
+*/
+-- option 1
+SELECT product_id, vendor_id, market_date, customer_id, quantity, cost_to_customer_per_qty, transaction_time, (quantity * cost_to_customer_per_qty) as price from customer_purchases
+where customer_id >= 8 AND customer_id <=10;
+
+-- option 2
+SELECT product_id, vendor_id, market_date, customer_id, quantity, cost_to_customer_per_qty, transaction_time, (quantity * cost_to_customer_per_qty) as price from customer_purchases
+where customer_id BETWEEN 8 AND 10;
+
+--CASE
+/* 1. Products can be sold by the individual unit or by bulk measures like lbs. or oz. 
+Using the product table, write a query that outputs the product_id and product_name
+columns and add a column called prod_qty_type_condensed that displays the word “unit” 
+if the product_qty_type is “unit,” and otherwise displays the word “bulk.” */
+SELECT product_id, product_name, product_size, product_category_id, product_qty_type,
+CASE WHEN product_qty_type = 'unit' THEN 'unit'
+	ELSE 'bulk'
+	END AS prod_qty_type_condensed
+FROM product;
+
+
+/* 2. We want to flag all of the different types of pepper products that are sold at the market. 
+add a column to the previous query called pepper_flag that outputs a 1 if the product_name 
+contains the word “pepper” (regardless of capitalization), and otherwise outputs 0. */
+SELECT product_id, product_name, product_size, product_category_id, product_qty_type,
+CASE WHEN product_qty_type = 'unit' THEN 'unit'
+	ELSE 'bulk'
+	END AS prod_qty_type_condensed,
+
+CASE WHEN product_name LIKE '%pepper%' THEN 1
+	ELSE 0
+	END AS pepper_flag
+
+FROM product;
+
+
+--JOIN
+/* 1. Write a query that INNER JOINs the vendor table to the vendor_booth_assignments table on the 
+vendor_id field they both have in common, and sorts the result by vendor_name, then market_date. */
+
+SELECT v.vendor_id, vendor_name, vendor_type, vendor_owner_first_name, vendor_owner_last_name, booth_number, market_date 
+FROM vendor AS v
+INNER JOIN vendor_booth_assignments AS vb
+	ON v.vendor_id = vb.vendor_id
+ORDER BY vendor_name, market_date;
+
+/* SECTION 3 */
+
+-- AGGREGATE
+/* 1. Write a query that determines how many times each vendor has rented a booth 
+at the farmer’s market by counting the vendor booth assignments per vendor_id. */
+SELECT vendor_id ,COUNT(booth_number) AS number_of_booths
+FROM vendor_booth_assignments
+GROUP BY vendor_id;
+
+/* 2. The Farmer’s Market Customer Appreciation Committee wants to give a bumper 
+sticker to everyone who has ever spent more than $2000 at the market. Write a query that generates a list 
+of customers for them to give stickers to, sorted by last name, then first name. 
+
+HINT: This query requires you to join two tables, use an aggregate function, and use the HAVING keyword. */
+SELECT
+c.customer_id
+,customer_last_name
+,customer_first_name
+,SUM(quantity*cost_to_customer_per_qty) as total_spend 
+FROM customer_purchases AS cp
+
+INNER JOIN customer AS c
+	ON cp.customer_id = c.customer_id
+
+GROUP BY c.customer_id
+HAVING total_spend > 2000
+ORDER BY customer_last_name, customer_first_name;
+
+--Temp Table
+/* 1. Insert the original vendor table into a temp.new_vendor and then add a 10th vendor: 
+Thomass Superfood Store, a Fresh Focused store, owned by Thomas Rosenthal
+
+HINT: This is two total queries -- first create the table from the original, then insert the new 10th vendor. 
+When inserting the new vendor, you need to appropriately align the columns to be inserted 
+(there are five columns to be inserted, I've given you the details, but not the syntax) 
+
+-> To insert the new row use VALUES, specifying the value you want for each column:
+VALUES(col1,col2,col3,col4,col5) 
+*/
+DROP TABLE IF EXISTS temp.new_vendor;
+
+--make the table
+CREATE TABLE temp.new_vendor AS
+
+-- definition of the table
+SELECT * FROM vendor;
+
+INSERT INTO new_vendor (vendor_id, vendor_name, vendor_type, vendor_owner_first_name, vendor_owner_last_name)
+VALUES (10, 'Thomass Superfood Store', 'Fresh Focused store', 'Thomas', 'Rosenthal');
+
+SELECT * FROM new_vendor;
+-- Date
+/*1. Get the customer_id, month, and year (in separate columns) of every purchase in the customer_purchases table.
+
+HINT: you might need to search for strfrtime modifers sqlite on the web to know what the modifers for month 
+and year are! */
+
+
+
+/* 2. Using the previous query as a base, determine how much money each customer spent in April 2022. 
+Remember that money spent is quantity*cost_to_customer_per_qty. 
+
+HINTS: you will need to AGGREGATE, GROUP BY, and filter...
+but remember, STRFTIME returns a STRING for your WHERE statement!! */
+