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Assignment 2 #2

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9f0664f
solving anagram
beshermahrouka Aug 29, 2024
21ad389
solving anagram
beshermahrouka Aug 29, 2024
2e19bfa
assignment 2 solution
beshermahrouka Sep 7, 2024
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114 changes: 101 additions & 13 deletions 02_activities/assignments/assignment_1.ipynb
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Original file line number Diff line number Diff line change
Expand Up @@ -56,32 +56,81 @@
},
{
"cell_type": "code",
"execution_count": null,
"execution_count": 11,
"metadata": {},
"outputs": [],
"outputs": [
{
"data": {
"text/plain": [
"True"
]
},
"execution_count": 11,
"metadata": {},
"output_type": "execute_result"
}
],
"source": [
"# This is a function, which we will learn more about next week. For testing purposes, we will write our code in the function\n",
"def anagram_checker(word_a, word_b):\n",
" # Your code here\n",
"\n",
" #convert all letters to lower case so it does not effects the comparision\n",
" word_a = word_a.lower()\n",
" word_b = word_b.lower()\n",
" # Create dictionaries to count the frequency of each character\n",
" char_count1 = {}\n",
" char_count2 = {}\n",
" \n",
" # Count characters in word_a\n",
" for char in word_a:\n",
" char_count1[char] = char_count1.get(char, 0) + 1\n",
" \n",
" # Count characters in word_b\n",
" for char in word_b:\n",
" char_count2[char] = char_count2.get(char, 0) + 1\n",
" \n",
" # Compare the two dictionaries if they have the same freq\n",
" return char_count1 == char_count2\n",
"# Run your code to check using the words below:\n",
"anagram_checker(\"Silent\", \"listen\")"
]
},
{
"cell_type": "code",
"execution_count": null,
"execution_count": 12,
"metadata": {},
"outputs": [],
"outputs": [
{
"data": {
"text/plain": [
"False"
]
},
"execution_count": 12,
"metadata": {},
"output_type": "execute_result"
}
],
"source": [
"anagram_checker(\"Silent\", \"Night\")"
]
},
{
"cell_type": "code",
"execution_count": null,
"execution_count": 13,
"metadata": {},
"outputs": [],
"outputs": [
{
"data": {
"text/plain": [
"True"
]
},
"execution_count": 13,
"metadata": {},
"output_type": "execute_result"
}
],
"source": [
"anagram_checker(\"night\", \"Thing\")"
]
Expand All @@ -97,22 +146,61 @@
},
{
"cell_type": "code",
"execution_count": null,
"execution_count": 10,
"metadata": {},
"outputs": [],
"outputs": [
{
"data": {
"text/plain": [
"True"
]
},
"execution_count": 10,
"metadata": {},
"output_type": "execute_result"
}
],
"source": [
"def anagram_checker(word_a, word_b, is_case_sensitive):\n",
" # Modify your existing code here\n",
"\n",
" # if it is not case sensitve, convert all letters to lower case so it does not effects the comparision\n",
" if not is_case_sensitive:\n",
" word_a = word_a.lower()\n",
" word_b = word_b.lower()\n",
" # Create dictionaries to count the frequency of each character\n",
" char_count1 = {}\n",
" char_count2 = {}\n",
" \n",
" # Count characters in word_a\n",
" for char in word_a:\n",
" char_count1[char] = char_count1.get(char, 0) + 1\n",
" \n",
" # Count characters in word_b\n",
" for char in word_b:\n",
" char_count2[char] = char_count2.get(char, 0) + 1\n",
" \n",
" # Compare the two dictionaries if they have the same freq\n",
" return char_count1 == char_count2\n",
"# Run your code to check using the words below:\n",
"anagram_checker(\"Silent\", \"listen\", False) # True"
]
},
{
"cell_type": "code",
"execution_count": null,
"execution_count": 9,
"metadata": {},
"outputs": [],
"outputs": [
{
"data": {
"text/plain": [
"False"
]
},
"execution_count": 9,
"metadata": {},
"output_type": "execute_result"
}
],
"source": [
"anagram_checker(\"Silent\", \"Listen\", True) # False"
]
Expand Down Expand Up @@ -144,7 +232,7 @@
"name": "python",
"nbconvert_exporter": "python",
"pygments_lexer": "ipython3",
"version": "3.11.8"
"version": "3.9.18"
}
},
"nbformat": 4,
Expand Down
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