dnysius · dnysius · Dec 11, 2024 · Dec 11, 2024 · Dec 11, 2024 · Dec 11, 2024
diff --git a/02_activities/assignments/Assignment2.md b/02_activities/assignments/Assignment2.md
@@ -54,7 +54,10 @@ The store wants to keep customer addresses. Propose two architectures for the CU
 **HINT:** search type 1 vs type 2 slowly changing dimensions. 
 
 ```
-Your answer...
+CUSTOMER_ADDRESS table can be linked to the customer table via a customer_id field. It will contain fields to store address, country information, as well as system information such as the last updated date and the entry creation date. It may also be useful to allow for multiple addresses per customer, so the customer_id field may not be unique; instead, we can have a flag to indicate if an address listed for a customer is the primary/default address to be used in the profile or as a shipping address. 
+1. Type 1 Slowly Changing Dimension will overwrite rows the table and does not retain history. 
+2. Type 2 Slowly Changing Dimension will retain the change history in the table.
+Considering addresses is sensitive info it would be best to use Type 1 architecture. This minimizes the amount of unused sensitive information being stored in the database. Only when there is a need in analytics/operations to keep the historical information, should Type 2 be considered.
 ```
 
 ***

diff --git a/02_activities/assignments/SQL Assignment 1.drawio.png b/02_activities/assignments/SQL Assignment 1.drawio.png
diff --git a/02_activities/assignments/assignment1.sql b/02_activities/assignments/assignment1.sql
@@ -4,21 +4,41 @@
 
 --SELECT
 /* 1. Write a query that returns everything in the customer table. */
-
+SELECT 
+	* 
+FROM 
+	customer
 
 
 /* 2. Write a query that displays all of the columns and 10 rows from the cus- tomer table, 
 sorted by customer_last_name, then customer_first_ name. */
-
+SELECT 
+	* 
+FROM 
+	customer 
+ORDER BY 
+	customer_last_name, 
+	customer_first_name 
+LIMIT 10
 
 
 --WHERE
 /* 1. Write a query that returns all customer purchases of product IDs 4 and 9. */
 -- option 1
-
+SELECT 
+	* 
+FROM 
+	customer_purchases 
+WHERE 
+	product_id IN (4, 9)
 
 -- option 2
-
+SELECT 
+	* 
+FROM 
+	customer_purchases 
+WHERE 
+	product_id = 4 OR product_id= 9
 
 
 /*2. Write a query that returns all customer purchases and a new calculated column 'price' (quantity * cost_to_customer_per_qty), 
@@ -27,9 +47,23 @@ filtered by vendor IDs between 8 and 10 (inclusive) using either:
 	2.  one condition using BETWEEN
 */
 -- option 1
+SELECT 
+	quantity*cost_to_customer_per_qty AS price, 
+	* 
+FROM 
+	customer_purchases 
+WHERE 
+	vendor_id >= 8 AND vendor_id<=10
 
 
 -- option 2
+SELECT 
+	quantity*cost_to_customer_per_qty AS price, 
+	* 
+FROM 
+	customer_purchases 
+WHERE 
+	vendor_id BETWEEN 8 AND 10
 
 
 
@@ -38,19 +72,36 @@ filtered by vendor IDs between 8 and 10 (inclusive) using either:
 Using the product table, write a query that outputs the product_id and product_name
 columns and add a column called prod_qty_type_condensed that displays the word “unit” 
 if the product_qty_type is “unit,” and otherwise displays the word “bulk.” */
-
+SELECT 
+	*, 
+	CASE product_qty_type WHEN  'unit' THEN 'unit' ELSE 'bulk' END AS prod_qty_type_condensed 
+FROM 
+	product
 
 
 /* 2. We want to flag all of the different types of pepper products that are sold at the market. 
 add a column to the previous query called pepper_flag that outputs a 1 if the product_name 
 contains the word “pepper” (regardless of capitalization), and otherwise outputs 0. */
-
+SELECT 
+	*, 
+	CASE  WHEN product_name LIKE '%pepper%' THEN 1 ELSE 0 END AS pepper_flag 
+FROM product
 
 
 --JOIN
 /* 1. Write a query that INNER JOINs the vendor table to the vendor_booth_assignments table on the 
 vendor_id field they both have in common, and sorts the result by vendor_name, then market_date. */
-
+SELECT 
+	* 
+FROM 
+	vendor 
+JOIN 
+	vendor_booth_assignments 
+ON  
+	vendor.vendor_id = vendor_booth_assignments.vendor_id 
+ORDER BY 
+	vendor.vendor_name, 
+	vendor_booth_assignments.market_date
 
 
 
@@ -59,15 +110,35 @@ vendor_id field they both have in common, and sorts the result by vendor_name, t
 -- AGGREGATE
 /* 1. Write a query that determines how many times each vendor has rented a booth 
 at the farmer’s market by counting the vendor booth assignments per vendor_id. */
-
+SELECT 
+	vendor_id, 
+	count(vendor_id) as num_rent 
+FROM 
+	vendor_booth_assignments 
+GROUP BY vendor_id
 
 
 /* 2. The Farmer’s Market Customer Appreciation Committee wants to give a bumper 
 sticker to everyone who has ever spent more than $2000 at the market. Write a query that generates a list 
 of customers for them to give stickers to, sorted by last name, then first name. 
 
 HINT: This query requires you to join two tables, use an aggregate function, and use the HAVING keyword. */
-
+SELECT c.customer_last_name, 
+	c.customer_first_name, 
+	SUM(p.quantity*p.cost_to_customer_per_qty) as total_purchases 
+FROM 
+	customer c 
+JOIN 
+	customer_purchases p 
+ON 
+	c.customer_id = p.customer_id 
+GROUP BY 
+	c.customer_id 
+HAVING 
+	SUM(p.quantity*p.cost_to_customer_per_qty) >2000 
+ORDER BY 
+	c.customer_last_name, 
+	c.customer_first_name
 
 
 --Temp Table
@@ -81,20 +152,52 @@ When inserting the new vendor, you need to appropriately align the columns to be
 -> To insert the new row use VALUES, specifying the value you want for each column:
 VALUES(col1,col2,col3,col4,col5) 
 */
-
-
+CREATE TABLE "temp"."new_vendor" (
+  "vendor_id" int(11) NOT NULL ,
+  "vendor_name" varchar(45) NOT NULL,
+  "vendor_type" varchar(45) NOT NULL,
+  "vendor_owner_first_name" varchar(45) NOT NULL,
+  "vendor_owner_last_name" varchar(45) NOT NULL,
+  PRIMARY KEY ("vendor_id"),
+  UNIQUE  ("vendor_id"),
+  UNIQUE  ("vendor_name")
+)
+INSERT INTO 
+	new_vendor 
+SELECT 
+	* 
+FROM 
+	vendor
+INSERT INTO 
+	temp.new_vendor 
+VALUES 
+	(10, "Thomass Superfood Store", "Fresh Focused", "Thomas", "Rosenthal")
 
 -- Date
 /*1. Get the customer_id, month, and year (in separate columns) of every purchase in the customer_purchases table.
 
 HINT: you might need to search for strfrtime modifers sqlite on the web to know what the modifers for month 
 and year are! */
-
+SELECT 
+	customer_id, 
+	STRFTIME('%Y', market_date) as year, 
+	STRFTIME('%m', market_date) AS month, 
+	* 
+FROM 
+	customer_purchases
 
 
 /* 2. Using the previous query as a base, determine how much money each customer spent in April 2022. 
 Remember that money spent is quantity*cost_to_customer_per_qty. 
 
 HINTS: you will need to AGGREGATE, GROUP BY, and filter...
 but remember, STRFTIME returns a STRING for your WHERE statement!! */
-
+SELECT 
+	customer_id, 
+	SUM(quantity*cost_to_customer_per_qty) AS total_spending 
+FROM 
+	customer_purchases
+WHERE 
+	STRFTIME('%Y', market_date) ='2022' AND STRFTIME('%m', market_date) = '05' 
+GROUP BY 
+	customer_id
diff --git a/02_activities/assignments/assignment2 - model design prompt 1.png b/02_activities/assignments/assignment2 - model design prompt 1.png
diff --git a/02_activities/assignments/assignment2 - model design prompt 2.png b/02_activities/assignments/assignment2 - model design prompt 2.png