msselizabeth · msselizabeth · Apr 19, 2025 · Apr 19, 2025
diff --git a/02_activities/assignment-one-diagram.png b/02_activities/assignment-one-diagram.png
diff --git a/02_activities/assignments/assignment1.sql b/02_activities/assignments/assignment1.sql
@@ -4,21 +4,28 @@
 
 --SELECT
 /* 1. Write a query that returns everything in the customer table. */
-
+select * from customer;
 
 
 /* 2. Write a query that displays all of the columns and 10 rows from the cus- tomer table, 
 sorted by customer_last_name, then customer_first_ name. */
-
+select * from customer
+order by customer_last_name, customer_first_name
+limit 10;
 
 
 --WHERE
 /* 1. Write a query that returns all customer purchases of product IDs 4 and 9. */
 -- option 1
-
+select * from customer_purchases
+where product_id = 7 or product_id = 9;
 
 -- option 2
+select * from customer_purchases
+where product_id = 7;
 
+select * from customer_purchases
+where product_id = 9;
 
 
 /*2. Write a query that returns all customer purchases and a new calculated column 'price' (quantity * cost_to_customer_per_qty), 
@@ -27,30 +34,57 @@ filtered by vendor IDs between 8 and 10 (inclusive) using either:
 	2.  one condition using BETWEEN
 */
 -- option 1
-
+select *, 
+       (quantity * cost_to_customer_per_qty) as price
+from customer_purchases
+where vendor_id >= 8 AND vendor_id <= 10;
 
 -- option 2
-
+select *, 
+       (quantity * cost_to_customer_per_qty) as price
+from customer_purchases
+where vendor_id between 8 and 10;
 
 
 --CASE
 /* 1. Products can be sold by the individual unit or by bulk measures like lbs. or oz. 
 Using the product table, write a query that outputs the product_id and product_name
 columns and add a column called prod_qty_type_condensed that displays the word “unit” 
 if the product_qty_type is “unit,” and otherwise displays the word “bulk.” */
-
+select 
+   product_id, 
+   product_name, 
+   (case 
+    when product_qty_type = 'unit' then 'unit'
+    else 'bulk'
+    end) as prod_qty_type_condensed
+from product;
 
 
 /* 2. We want to flag all of the different types of pepper products that are sold at the market. 
 add a column to the previous query called pepper_flag that outputs a 1 if the product_name 
 contains the word “pepper” (regardless of capitalization), and otherwise outputs 0. */
-
+select 
+   product_id, 
+   product_name, 
+   (case 
+    when product_qty_type = 'unit' then 'unit'
+    else 'bulk'
+    end) as prod_qty_type_condensed,
+    (
+    case when product_name like '%pepper%' then 1
+      else 0
+      end
+    ) as pepper_flag
+from product
 
 
 --JOIN
 /* 1. Write a query that INNER JOINs the vendor table to the vendor_booth_assignments table on the 
 vendor_id field they both have in common, and sorts the result by vendor_name, then market_date. */
-
+select v.vendor_name, vba.market_date from vendor_booth_assignments vba
+join vendor v on v.vendor_id = vba.vendor_id
+order by v.vendor_name, vba.market_date
 
 
 
@@ -59,6 +93,11 @@ vendor_id field they both have in common, and sorts the result by vendor_name, t
 -- AGGREGATE
 /* 1. Write a query that determines how many times each vendor has rented a booth 
 at the farmer’s market by counting the vendor booth assignments per vendor_id. */
+select
+ *,
+  count(*) as booth_rental_count
+from vendor_booth_assignments
+group by vendor_id
 
 
 
@@ -67,6 +106,16 @@ sticker to everyone who has ever spent more than $2000 at the market. Write a qu
 of customers for them to give stickers to, sorted by last name, then first name. 
 
 HINT: This query requires you to join two tables, use an aggregate function, and use the HAVING keyword. */
+select 
+c.customer_id,
+c.customer_first_name, 
+c.customer_last_name,
+SUM(cp.quantity * cp.cost_to_customer_per_qty) as total
+from customer_purchases cp
+join customer c on c.customer_id = cp.customer_id
+group by c.customer_id, c.customer_last_name, c.customer_first_name
+having SUM(cp.quantity * cp.cost_to_customer_per_qty) > 2000
+order by c.customer_last_name, c.customer_first_name
 
 
 
@@ -81,6 +130,23 @@ When inserting the new vendor, you need to appropriately align the columns to be
 -> To insert the new row use VALUES, specifying the value you want for each column:
 VALUES(col1,col2,col3,col4,col5) 
 */
+create table copy_vendor as
+select * from vendor;
+
+insert into copy_vendor (
+  vendor_id,
+  vendor_name,
+  vendor_type,
+  vendor_owner_first_name,
+  vendor_owner_last_name
+)
+values (
+  10,
+  'Thomass Superfood Store',
+  'Fresh Focused store',
+  'Thomas',
+  'Rosenthal'
+);
 
 
 
@@ -89,6 +155,11 @@ VALUES(col1,col2,col3,col4,col5)
 
 HINT: you might need to search for strfrtime modifers sqlite on the web to know what the modifers for month 
 and year are! */
+select
+  customer_id,
+  strftime('%m', market_date) as month,
+  strftime('%Y', market_date) as year
+from customer_purchases;
 
 
 
@@ -98,3 +169,11 @@ Remember that money spent is quantity*cost_to_customer_per_qty.
 HINTS: you will need to AGGREGATE, GROUP BY, and filter...
 but remember, STRFTIME returns a STRING for your WHERE statement!! */
 
+select
+  customer_id,
+  strftime('%m', market_date) as month,
+  strftime('%Y', market_date) as year,
+  SUM(quantity * cost_to_customer_per_qty) as total_spent
+from customer_purchases
+where strftime('%m', market_date) = '04' and strftime('%Y', market_date) = '2022'
+group by customer_id