qint99 · qint99 · Dec 14, 2024 · Dec 22, 2024 · Dec 22, 2024
diff --git a/02_activities/assignments/Assignment1.md b/02_activities/assignments/Assignment1.md
@@ -105,6 +105,10 @@ Please do not pick the exact same tables that I have already diagrammed. For exa
 	- <img src="./images/01_farmers_market_conceptual_model.png" width="600">
 - The column names can be found in a few spots (DB Schema window in the bottom right, the Database Structure tab in the main window by expanding each table entry, at the top of the Browse Data tab in the main window)
 
+
+
+
+
 ***
 
 ## Section 2:

diff --git a/02_activities/assignments/Assignment2.md b/02_activities/assignments/Assignment2.md
@@ -55,8 +55,26 @@ The store wants to keep customer addresses. Propose two architectures for the CU
 
 ```
 Your answer...
-```
-
+For managing customer addresses, I suggest two distinct architectures based on whether we want to overwrite old addresses (type 1) or retain historical changes (type 2):
+
+for type 1: Customer Address (Current Address Only)
+customer_id (PK, FK) - (PK & FK)
+address_line
+city
+state
+zip_code
+country
+
+for type 2: historical history (all addresses included)
+address_id (PK) 
+customer_id (FK) 
+address_line
+city
+state
+zip_code
+country
+
+for address iD, we will assign each address a new address_ID
 ***
 
 ## Section 2:

diff --git a/02_activities/assignments/Farmersmarket_Logical_Diagram(Partial).drawio.png b/02_activities/assignments/Farmersmarket_Logical_Diagram(Partial).drawio.png
diff --git a/02_activities/assignments/Prompt 1.png b/02_activities/assignments/Prompt 1.png
diff --git a/02_activities/assignments/Prompt 2.png b/02_activities/assignments/Prompt 2.png
diff --git a/02_activities/assignments/assignment1.sql b/02_activities/assignments/assignment1.sql
@@ -4,21 +4,27 @@
 
 --SELECT
 /* 1. Write a query that returns everything in the customer table. */
-
+SELECT * FROM customer;
 
 
 /* 2. Write a query that displays all of the columns and 10 rows from the cus- tomer table, 
 sorted by customer_last_name, then customer_first_ name. */
-
+SELECT * FROM customer
+ORDER BY customer_last_name, customer_first_name
+LIMIT 10;       
 
 
 --WHERE
 /* 1. Write a query that returns all customer purchases of product IDs 4 and 9. */
 -- option 1
+SELECT * FROM customer_purchases
+WHERE product_id IN (4, 9);    
+-- only returns product_id = 4 because there is no product_id = 9 on customer_purchases
 
 
 -- option 2
-
+SELECT * FROM customer_purchases
+WHERE product_id = 4 OR product_id = 9
 
 
 /*2. Write a query that returns all customer purchases and a new calculated column 'price' (quantity * cost_to_customer_per_qty), 
@@ -27,30 +33,58 @@ filtered by vendor IDs between 8 and 10 (inclusive) using either:
 	2.  one condition using BETWEEN
 */
 -- option 1
-
+	SELECT *
+	, (quantity * cost_to_customer_per_qty) AS price
+	FROM customer_purchases
+	WHERE vendor_id BETWEEN 8 AND 10;
 
 -- option 2
-
+	SELECT *
+		, (quantity * cost_to_customer_per_qty) AS price
+	FROM customer_purchases
+	WHERE vendor_id BETWEEN 8 AND 10;
 
 
 --CASE
 /* 1. Products can be sold by the individual unit or by bulk measures like lbs. or oz. 
 Using the product table, write a query that outputs the product_id and product_name
 columns and add a column called prod_qty_type_condensed that displays the word “unit” 
 if the product_qty_type is “unit,” and otherwise displays the word “bulk.” */
+SELECT product_id, product_name,
+		CASE
+					WHEN product_qty_type = 'unit' THEN 'unit'
+					ELSE 'bulk'
+		END AS prod_qty_type_condensed
+FROM product;
 
 
 
 /* 2. We want to flag all of the different types of pepper products that are sold at the market. 
 add a column to the previous query called pepper_flag that outputs a 1 if the product_name 
 contains the word “pepper” (regardless of capitalization), and otherwise outputs 0. */
-
+SELECT product_id, product_name,
+		CASE
+					WHEN product_qty_type = 'unit' THEN 'unit'
+					ELSE 'bulk'
+		END AS prod_qty_type_condensed,
+		CASE
+					WHEN LOWER(product_name) LIKE '%pepper%' THEN 1
+					ELSE 0
+		END AS pepper_flag
+FROM product;
 
 
 --JOIN
 /* 1. Write a query that INNER JOINs the vendor table to the vendor_booth_assignments table on the 
 vendor_id field they both have in common, and sorts the result by vendor_name, then market_date. */
-
+SELECT 
+    v.vendor_id, 
+    v.vendor_name, 
+    vba.market_date
+ FROM  vendor AS v
+ INNER JOIN vendor_booth_assignments AS vba
+ ON  v.vendor_id = vba.vendor_id
+ORDER BY v.vendor_name, vba.market_date;
 
 
 
@@ -59,15 +93,28 @@ vendor_id field they both have in common, and sorts the result by vendor_name, t
 -- AGGREGATE
 /* 1. Write a query that determines how many times each vendor has rented a booth 
 at the farmer’s market by counting the vendor booth assignments per vendor_id. */
-
+SELECT vendor_id
+    ,COUNT(*) AS  rental_times
+FROM  vendor_booth_assignments
+GROUP BY  vendor_id;
 
 
 /* 2. The Farmer’s Market Customer Appreciation Committee wants to give a bumper 
 sticker to everyone who has ever spent more than $2000 at the market. Write a query that generates a list 
 of customers for them to give stickers to, sorted by last name, then first name. 
 
 HINT: This query requires you to join two tables, use an aggregate function, and use the HAVING keyword. */
-
+SELECT 
+    c.customer_id, 
+    c.customer_first_name, 
+    c.customer_last_name, 
+    SUM(cp.quantity * cp.cost_to_customer_per_qty) AS total_spent
+FROM  customer AS c
+INNER JOIN customer_purchases AS cp
+ON  c.customer_id = cp.customer_id
+GROUP BY c.customer_id, c.customer_first_name, c.customer_last_name
+HAVING   total_spent > 2000
+ORDER BY  c.customer_last_name, c.customer_first_name;
 
 
 --Temp Table
@@ -81,7 +128,13 @@ When inserting the new vendor, you need to appropriately align the columns to be
 -> To insert the new row use VALUES, specifying the value you want for each column:
 VALUES(col1,col2,col3,col4,col5) 
 */
+CREATE TEMP TABLE new_vendor AS
+SELECT * FROM vendor;
+INSERT INTO new_vendor (vendor_id, vendor_name, vendor_type, vendor_owner_first_name, vendor_owner_last_name)
+VALUES (10, 'Thomass Superfood Store', 'Fresh Focused', 'Thomas', 'Rosenthal');
 
+-- test it OUT
+SELECT * FROM new_vendor;
 
 
 -- Date
@@ -90,6 +143,11 @@ VALUES(col1,col2,col3,col4,col5)
 HINT: you might need to search for strfrtime modifers sqlite on the web to know what the modifers for month 
 and year are! */
 
+SELECT 
+    customer_id, 
+    STRFTIME('%m', market_date) AS month, 
+    STRFTIME('%Y', market_date) AS year
+FROM customer_purchases;
 
 
 /* 2. Using the previous query as a base, determine how much money each customer spent in April 2022. 
@@ -98,3 +156,12 @@ Remember that money spent is quantity*cost_to_customer_per_qty.
 HINTS: you will need to AGGREGATE, GROUP BY, and filter...
 but remember, STRFTIME returns a STRING for your WHERE statement!! */
 
+SELECT 
+    customer_id, 
+    SUM(quantity * cost_to_customer_per_qty) AS total_spent
+FROM  customer_purchases
+WHERE 
+    STRFTIME('%m', market_date) = '04' 
+    AND STRFTIME('%Y', market_date) = '2022'
+GROUP BY 
+    customer_id;
-Original file line number
+Diff line change
@@ Expand Up @@
     	- <img src="./images/01_farmers_market_conceptual_model.png" width="600">
     - The column names can be found in a few spots (DB Schema window in the bottom right, the Database Structure tab in the main window by expanding each table entry, at the top of the Browse Data tab in the main window)
     ***
     ## Section 2:
@@ Expand Down @@