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4 changes: 3 additions & 1 deletion 02_activities/assignments/Assignment2.md
Original file line number Diff line number Diff line change
Expand Up @@ -54,7 +54,9 @@ The store wants to keep customer addresses. Propose two architectures for the CU
**HINT:** search type 1 vs type 2 slowly changing dimensions.

```
Your answer...
--Type 1 is the owerwrite method (most recent address remains)
--Type 2 is the history method (stores all past addresses with timestamps)

```

***
Expand Down
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127 changes: 119 additions & 8 deletions 02_activities/assignments/assignment2.sql
Original file line number Diff line number Diff line change
@@ -1,4 +1,9 @@
/* ASSIGNMENT 2 */

/*SECTION 1 - PROMPT 3 */
--Type 1 is the owerwrite method (most recent address remains)
--Type 2 is the history method (stores all past addresses with timestamps)

/* SECTION 2 */

-- COALESCE
Expand All @@ -20,6 +25,13 @@ The `||` values concatenate the columns into strings.
Edit the appropriate columns -- you're making two edits -- and the NULL rows will be fixed.
All the other rows will remain the same.) */

SELECT
product_name || ', ' || coalesce(product_size, '') || ' (' || coalesce(product_qty_type, '') || ')'
FROM product;

SELECT
product_name || ', ' || coalesce(product_size, 'unit') || ' (' || coalesce(product_qty_type, 'unit') || ')'
FROM product;


--Windowed Functions
Expand All @@ -32,18 +44,43 @@ each new market date for each customer, or select only the unique market dates p
(without purchase details) and number those visits.
HINT: One of these approaches uses ROW_NUMBER() and one uses DENSE_RANK(). */

SELECT
customer_id,
market_date,
row_number() OVER (PARTITION BY customer_id ORDER BY market_date) AS visit_number
FROM customer_purchases;


/* 2. Reverse the numbering of the query from a part so each customer’s most recent visit is labeled 1,
then write another query that uses this one as a subquery (or temp table) and filters the results to
only the customer’s most recent visit. */


--Reverse numbering
SELECT
customer_id,
market_date,
row_number () OVER (PARTITION BY customer_id ORDER BY market_date DESC) AS reversed_visit_number
FROM customer_purchases;

--Most recent visit
SELECT *
FROM (SELECT
customer_id,
market_date,
row_number() OVER
(PARTITION BY customer_id ORDER BY market_date DESC) AS reversed_visit_number FROM customer_purchases)
AS recent_visits
WHERE reversed_visit_number = 1;

/* 3. Using a COUNT() window function, include a value along with each row of the
customer_purchases table that indicates how many different times that customer has purchased that product_id. */


--Count Purchases of Product
SELECT
customer_id,
product_id,
count(*) OVER (PARTITION BY customer_id, product_id) AS product_purchase_count
FROM customer_purchases;

-- String manipulations
/* 1. Some product names in the product table have descriptions like "Jar" or "Organic".
Expand All @@ -57,11 +94,17 @@ Remove any trailing or leading whitespaces. Don't just use a case statement for

Hint: you might need to use INSTR(product_name,'-') to find the hyphens. INSTR will help split the column. */

SELECT
substr(product_name, instr(product_name, ' - ') + 2) AS description
FROM product
WHERE instr(product_name, ' - ') > 0;


/* 2. Filter the query to show any product_size value that contain a number with REGEXP. */


SELECT product_name, product_size
FROM product
WHERE product_size REGEXP '[0-9]';

-- UNION
/* 1. Using a UNION, write a query that displays the market dates with the highest and lowest total sales.
Expand All @@ -73,7 +116,27 @@ HINT: There are a possibly a few ways to do this query, but if you're struggling
3) Query the second temp table twice, once for the best day, once for the worst day,
with a UNION binding them. */


--1) Group Sales by Market Date
WITH sales_by_date AS
(SELECT market_date, sum(cost_to_customer_per_qty) AS total_sales
FROM customer_purchases
GROUP BY market_date),

--2) Rank Market Dates by Sales
ranked_dates AS
(SELECT market_date, total_sales,
rank() OVER(ORDER BY total_sales DESC) AS rank_high,
rank() OVER(ORDER BY total_sales ASC) AS rank_low
FROM sales_by_date)

--3) Query Best and Worst Days using UNION
SELECT market_date, total_sales
FROM ranked_dates
WHERE rank_high = 1
UNION
SELECT market_date, total_sales
FROM ranked_dates
WHERE rank_low = 1;


/* SECTION 3 */
Expand All @@ -89,27 +152,53 @@ Think a bit about the row counts: how many distinct vendors, product names are t
How many customers are there (y).
Before your final group by you should have the product of those two queries (x*y). */

--Cross Join:
--1) Vendor Product Pairs
WITH vendor_products AS
(SELECT v.vendor_name, p.product_name, vi.original_price
FROM vendor_inventory vi
JOIN vendor v ON vi.vendor_id = v.vendor_id
JOIN product p ON vi.product_id = p.product_id),

--2) Total Customers
total_customers AS ( SELECT count(*) AS customer_count FROM customer)

--3) Calculate Total Revenue
SELECT vp.vendor_name, vp.product_name, tc.customer_count * 5 * vp.original_price AS total_revenue
FROM vendor_products vp
CROSS JOIN total_customers tc
ORDER BY total_revenue DESC;

-- INSERT
/*1. Create a new table "product_units".
This table will contain only products where the `product_qty_type = 'unit'`.
It should use all of the columns from the product table, as well as a new column for the `CURRENT_TIMESTAMP`.
Name the timestamp column `snapshot_timestamp`. */

CREATE TABLE product_units AS
SELECT *,
CURRENT_TIMESTAMP AS snapshot_timestamp
FROM product
WHERE product_qty_type = 'unit';


/*2. Using `INSERT`, add a new row to the product_units table (with an updated timestamp).
This can be any product you desire (e.g. add another record for Apple Pie). */


INSERT INTO product_units (product_id, product_name, product_size, product_qty_type, snapshot_timestamp)
VALUES (101, 'Apple Pie', 'Large', 'unit', CURRENT_TIMESTAMP);

-- DELETE
/* 1. Delete the older record for the whatever product you added.

HINT: If you don't specify a WHERE clause, you are going to have a bad time.*/


DELETE FROM product_units
WHERE product_id = 101
AND snapshot_timestamp < (
SELECT max(snapshot_timestamp)
FROM product_units
WHERE product_id = 101);

-- UPDATE
/* 1.We want to add the current_quantity to the product_units table.
Expand All @@ -128,6 +217,28 @@ Finally, make sure you have a WHERE statement to update the right row,
you'll need to use product_units.product_id to refer to the correct row within the product_units table.
When you have all of these components, you can run the update statement. */

--1) ALTER - Add Column
ALTER TABLE product_units
ADD current_quantity INT;



--2) Last Quantity Per Product
SELECT
product_id,
coalesce(quantity, 0) AS last_quantity
FROM vendor_inventory
WHERE market_date = (SELECT max(market_date)
FROM vendor_inventory AS vi_sub
WHERE vi_sub.product_id = vendor_inventory.product_id);

--3) Update with WHERE statement

UPDATE product_units
SET current_quantity = (SELECT coalesce(quantity, 0)
FROM vendor_inventory
WHERE vendor_inventory.product_id = product_units.product_id
AND vendor_inventory.market_date = (SELECT max(market_date)
FROM vendor_inventory
WHERE vendor_inventory.product_id = product_units.product_id))
WHERE EXISTS
(SELECT 1 FROM vendor_inventory
WHERE vendor_inventory.product_id = product_units.product_id);