I have a construct where I have a for loop nested inside of a while loop in Java. Is there a way to call a break statement such that it exits both the for loop and the while loop?
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stackoverflow.com/questions/2545103/… there you go :)Lasse Espeholt– Lasse Espeholt2011-04-14 21:44:36 +00:00Commented Apr 14, 2011 at 21:44
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possible duplicate of Breaking out of nested loops in JavaNeil– Neil2012-05-18 21:17:59 +00:00Commented May 18, 2012 at 21:17
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5 Answers
You can use a 'labeled' break for this.
class BreakWithLabelDemo {
public static void main(String[] args) {
int[][] arrayOfInts = { { 32, 87, 3, 589 },
{ 12, 1076, 2000, 8 },
{ 622, 127, 77, 955 }
};
int searchfor = 12;
int i;
int j = 0;
boolean foundIt = false;
search:
for (i = 0; i < arrayOfInts.length; i++) {
for (j = 0; j < arrayOfInts[i].length; j++) {
if (arrayOfInts[i][j] == searchfor) {
foundIt = true;
break search;
}
}
}
if (foundIt) {
System.out.println("Found " + searchfor +
" at " + i + ", " + j);
} else {
System.out.println(searchfor
+ " not in the array");
}
}
}
Taken from: http://download.oracle.com/javase/tutorial/java/nutsandbolts/branch.html
Comments
You can do it in 3 ways:
- You can have while and for loops inside method, and then just call
return - You can break for-loop and set some flag which will cause exit in while-loop
- Use label (example below)
This is example for 3rd way (with label):
public void someMethod() {
// ...
search:
for (i = 0; i < arrayOfInts.length; i++) {
for (j = 0; j < arrayOfInts[i].length; j++) {
if (arrayOfInts[i][j] == searchfor) {
foundIt = true;
break search;
}
}
}
}
example from this site
In my opinion 1st and 2nd solution is elegant. Some programmers don't like labels.
Comments
For example:
out:
while(someCondition) {
for(int i = 0; i < someInteger; i++) {
if (someOtherCondition)
break out;
}
}