fix: use pd.concat() instead df.append() in to_dataframe() to avoid warning#1478
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fix: use pd.concat() instead df.append() in to_dataframe() to avoid warning#1478
pd.concat() instead df.append() in to_dataframe() to avoid warning#1478Conversation
Signed-off-by: anna-charlotte <[email protected]>
JoanFM
approved these changes
Apr 28, 2023
Signed-off-by: anna-charlotte <[email protected]>
JoanFM
reviewed
Apr 28, 2023
| df_doc = pd.DataFrame(_dict_to_access_paths(doc.dict())) | ||
| df = pd.concat([df, df_doc], ignore_index=True) | ||
| doc_dict = _dict_to_access_paths(doc.dict()) | ||
| doc_dict = {k: [v] for k, v in doc_dict.items()} |
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why do u need to convert them to list?
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pd.DataFrame.from_dict() expects a dict with the column names as keys, and the values have to be a list, therefore I wrap the value with a list
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like this v[0] would correspond to the first row, v[1] to the second row and so on. In our case we only have v[0] since len(v) = 1
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To avoid this warning, use
pd.concat():